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我已经使用json2csharp生成类。 有都好于var content = response.Content;
我也反序列化的主类:复杂的反序列化json与嵌套类c#
var responseData1 = JsonConvert.DeserializeObject<RootObjectChangeLocation>(content);
但我需要检索纬度和经度从这个类:
public class Location
{
public double lat { get; set; }
public double lng { get; set; }
}
我试图让var responseData1 = JsonConvert.DeserializeObject<Location>(content);
检索坐标。但是,如果我直接执行,则lat
和lng
在responseData1
中为空。我怎样才能得到它们? 这是由json2csharp生成的代码:
public class AddressComponent
{
public string long_name { get; set; }
public string short_name { get; set; }
public List<string> types { get; set; }
}
public class Northeast
{
public double lat { get; set; }
public double lng { get; set; }
}
public class Southwest
{
public double lat { get; set; }
public double lng { get; set; }
}
public class Bounds
{
public Northeast northeast { get; set; }
public Southwest southwest { get; set; }
}
public class Location
{
public double lat { get; set; }
public double lng { get; set; }
}
public class Northeast2
{
public double lat { get; set; }
public double lng { get; set; }
}
public class Southwest2
{
public double lat { get; set; }
public double lng { get; set; }
}
public class Viewport
{
public Northeast2 northeast { get; set; }
public Southwest2 southwest { get; set; }
}
public class Geometry
{
public Bounds bounds { get; set; }
public Location location { get; set; }
public string location_type { get; set; }
public Viewport viewport { get; set; }
}
public class Result
{
public List<AddressComponent> address_components { get; set; }
public string formatted_address { get; set; }
public Geometry geometry { get; set; }
public string place_id { get; set; }
public List<string> types { get; set; }
}
public class RootObjectChangeLocation
{
public List<Result> results { get; set; }
public string status { get; set; }
}
的jsonString是:
{
"results" : [
{
"address_components" : [
{
"long_name" : "Vinnytsia",
"short_name" : "Vinnytsia",
"types" : [ "locality", "political" ]
},
{
"long_name" : "Vinnyts'ka city council",
"short_name" : "Vinnyts'ka city council",
"types" : [ "administrative_area_level_3", "political" ]
},
{
"long_name" : "Vinnyts'ka oblast",
"short_name" : "Vinnyts'ka oblast",
"types" : [ "administrative_area_level_1", "political" ]
},
{
"long_name" : "Ukraine",
"short_name" : "UA",
"types" : [ "country", "political" ]
}
],
"formatted_address" : "Vinnytsia, Vinnyts'ka oblast, Ukraine",
"geometry" : {
"bounds" : {
"northeast" : {
"lat" : 49.27902,
"lng" : 28.5710879
},
"southwest" : {
"lat" : 49.190448,
"lng" : 28.3681799
}
},
"location" : {
"lat" : 49.233083,
"lng" : 28.468217
},
"location_type" : "APPROXIMATE",
"viewport" : {
"northeast" : {
"lat" : 49.27902,
"lng" : 28.5710879
},
"southwest" : {
"lat" : 49.1906116,
"lng" : 28.3681799
}
}
},
"place_id" : "ChIJiWRaGWVbLUcR_nTd7lnh1Ms",
"types" : [ "locality", "political" ]
}
],
"status" : "OK"
}
因此,要找到解决方案......是什么问题? –
*我需要添加更多的细节来发布这个问题... * - 然后请在提问之前这样做。你在找这个吗? [Google地理编码Json解析C#中的问题](https://stackoverflow.com/q/28371365/3744182)。 – dbc
请分享您尝试解码的JSON。 – dbc