NodeJS中的JavaScript类和模块

Question

我很难理解如何将单独的.js文件导入到我的index.js节点文件中。

我创建了一个文件pokemon.js，如下图所示：

var pokemon = (function(){ 

    function Pokemon(name) { 

    this.name = name; 
    console.log("pokemon"); 
    } 

})(); 

module.exports.Pokemon = pokemon; 

我index.js

，现在我想使用它：

var Pokemon = require('./models/pokemon.js'); 

//我怎么叫口袋妖怪功能？

UPDATE：

var Pokemon = require('./models/models.js'); 
var app = express(); 

var pokemons = []; 

app.get("/pokemon/all",function(req,res){ 

    var pokemon = Pokemon("Pikachu"); // Pokemon is not a function 



}) 

这里是我找到了解决办法：

models.js：

module.exports = function(name) { 
    this.name = name; 
} 

index.js: 

var Pokemon = require('./models/models.js'); 
var app = express(); 

var pokemons = []; 

app.get("/pokemon/all",function(req,res){ 

    var pokemon = new Pokemon('Pikachu'); 
    pokemons.push(pokemon); 
    res.json(pokemons); 

}) 

Answer 1

我看你要导出的对象构造。

pokemon.js

function Pokemon(name){ 
    this.name = name; 
    console.log(this.name); 
} 
// if any prototype 
Pokemon.prototype.serviceOne = function(){ }; 
Pokemon.prototype.serviceTwo = function(){ }; 


module.exports = Pokemon; 

index.js

var Pokemon = require('path/to/pokemon'); 
app.get("/pokemon/all",function(req,res){ 

    var pikachu= new Pokemon("Pikachu"); 
    pikachu.serviceOne(); 
    pikachu.serviceTwo(); 

}) 

Answer 2

的由@catta提供的只是一个小错误尝试：

var pokemon = function(name) { 
this.name = name; 
console.log("pokemon"); 
} 
module.exports.Pokemon = pokemon; 

在index.js

var Pokemon = require('./models.js'); 
Pokemon.Pokemon('name') //output name 

Answer 3

pokemon.js

var pokemon = function(str){ 
    this.name = str; 
    console.log(this.name); 
}; 
module.exports.Pokemon = pokemon; 

main.js

var Pokemon = require('./models/models.js'); 
var app = express(); 
var pokemons = []; 
app.get("/pokemon/all",function(req,res){ 
    pokemons.push(Pokemon.Pokemon("Pikachu")); 
}) 

当您设置VAR关键要求是该文件只是引用。因此，你需要 “Pokemon.Pokemon（）”