GROUP BY表达式必须至少包含... UNION查询

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我有一个大的查询，实际上是一个视图，它在Oracle中工作，但不在MS-SQL Server中。 UNION查询的后半部分将有硬编码值。GROUP BY表达式必须至少包含... UNION查询

我发布了在Oracle 11g中工作的原始查询，虽然我尝试了另一种方法，它没有两个硬编码值0'财务'。该尝试发布在底部。

我收到的错误是：每个GROUP BY表达式都必须包含至少一个不是外部引用的列。

SELECT 
    RECOVERYTXNLEDGER.TXN_ID    AS TXN_ID, 
    RECOVERYTXNLEDGER.REC_PROC_ID   AS RECORD_PROC_ID, 
    RECOVERYPROCESS.REC_PROC_NAME   AS RECORD_PROC_NAME, 
    RECOVERYPROCESS.REC_PROC_TYPE_ID  AS RECORD_PROC_TYPE_ID, 
    RECOVERYPROCTYPE.REC_PROC_TYPE_NAME  AS RECORD_PROC_TYPE_NAME, 
    RECOVERYPROCESS.REC_PROC_SEQ   AS RECORD_PROC_SEQUENCE_NUM, 
    RECOVERYTXNLEDGER.SVC_ID    AS SERVICE_ID, 
    SERVICECATALOG.SVC_REF     AS SERVICE_REFERENCE, 
    SERVICECATALOG.SVC_DESC     AS SERVICE_DESCRIPTION, 
    SERVICECATALOG.SDG_ID     AS SERVICE_STUDY_GROUP_ID, 
    STUDYGROUP1.SDG_REF      AS SERVICE_STUDY_GROUP_REF, 
    STUDYGROUP1.SDG_DESC     AS SERVICE_STUDY_GROUP_DESC, 
    RECOVERYTXNLEDGER.SVC_PER_ID   AS SERVICE_PERIOD_ID, 
    PERIOD1.PER_REF       AS SERVICE_PERIOD_REFERENCE, 
    PERIOD1.PER_DESC      AS SERVICE_PERIOD_DESCRIPT, 
    RECOVERYTXNLEDGER.SVC_SCN_ID   AS SERVICE_SCENARIO_ID, 
    SCENARIO1.SCN_DESC      AS SERVICE_SCENARIO_DESC, 
    RECOVERYTXNLEDGER.SVC_RATE    AS SERVICE_RATE, 
    RECOVERYTXNLEDGER.REC_TRANS_TYPE_ID  AS TRANS_TYPE_ID, 
    RECOVERYTRANSTYPE.REC_TRANS_TYPE_NAME AS TRANS_TYPE_NAME, 
    RECOVERYTXNLEDGER.CUST_ACCT_REF   AS CUSToMER_ACCOUNT, 
    RECOVERYTXNLEDGER.ORG_REF    AS ORGANIZATION_REFERENCE, 
    ORGANIZATION.ORG_DESC     AS ORGANIZATION_DESCRIPTION, 
    STUDYGROUP.SDG_ID      AS STUDY_GROUP_ID,      
    STUDYGROUP.SDG_REF      AS STUDY_GROUP_REFERENCE, 
    STUDYGROUP.SDG_DESC      AS STUDY_GROUP_DESCRIPT, 
    SUM(RECOVERYTXNLEDGER.REC_AMT)   AS TRANSACTION_AMOUNT, 
    RECOVERYTXNLEDGER.VOL_ID    AS VOLUME_ID, 
    VOLUMECATALOG.VOL_REF     AS VOLUME_REFERENCE, 
    VOLUMECATALOG.VOL_DESC     AS VOLUME_DESCRIPTION, 
    RECOVERYTXNLEDGER.VOL_PER_ID   AS VOLUME_PERIOD_ID, 
    PERIOD.PER_REF       AS VOLUME_PERIOD_REFERENCE, 
    PERIOD.PER_DESC       AS VOLUME_PERIOD_DESCRIPT, 
    RECOVERYTXNLEDGER.VOL_SCN_ID   AS VOLUME_SCENARIO_ID, 
    SCENARIO.SCN_DESC      AS VOLUME_SCENARIO_DESCRIPT, 
    RECOVERYTXNLEDGER.VOL_QTY    AS VOLUME_QUANTITY 
    FROM RECOVERYTXNLEDGER 
    INNER JOIN SCENARIO SCENARIO1 ON RECOVERYTXNLEDGER.SVC_SCN_ID = SCENARIO1.SCN_ID 
    INNER JOIN SERVICECATALOG ON RECOVERYTXNLEDGER.SVC_ID = SERVICECATALOG.SVC_ID 
    INNER JOIN STUDYGROUP STUDYGROUP1 ON SERVICECATALOG.SDG_ID = STUDYGROUP1.SDG_ID 
    INNER JOIN PERIOD PERIOD1 ON RECOVERYTXNLEDGER.SVC_PER_ID = PERIOD1.PER_ID 
    INNER JOIN RECOVERYPROCESS ON RECOVERYTXNLEDGER.REC_PROC_ID = RECOVERYPROCESS.REC_PROC_ID 
    INNER JOIN RECOVERYPROCTYPE ON RECOVERYPROCESS.REC_PROC_TYPE_ID = RECOVERYPROCTYPE.REC_PROC_TYPE_ID 
    INNER JOIN ORGANIZATION ON RECOVERYTXNLEDGER.ORG_REF = ORGANIZATION.ORG_REF 
    INNER JOIN STUDYGROUP ON ORGANIZATION.SDG_ID = STUDYGROUP.SDG_ID 
    INNER JOIN RECOVERYTRANSTYPE ON RECOVERYTXNLEDGER.REC_TRANS_TYPE_ID = RECOVERYTRANSTYPE.REC_TRANS_TYPE_ID 
    INNER JOIN VOLUMECATALOG ON RECOVERYTXNLEDGER.VOL_ID = VOLUMECATALOG.VOL_ID 
    INNER JOIN PERIOD ON RECOVERYTXNLEDGER.VOL_PER_ID = PERIOD.PER_ID 
    INNER JOIN SCENARIO ON RECOVERYTXNLEDGER.VOL_SCN_ID = SCENARIO.SCN_ID 
    GROUP BY 
    RECOVERYTXNLEDGER.REC_PROC_ID, 
    RECOVERYTXNLEDGER.TXN_ID, 
    RECOVERYPROCESS.REC_PROC_NAME, 
    RECOVERYPROCESS.REC_PROC_TYPE_ID, 
    RECOVERYPROCTYPE.REC_PROC_TYPE_NAME, 
    RECOVERYPROCESS.REC_PROC_SEQ, 
    RECOVERYTXNLEDGER.SVC_ID, 
    SERVICECATALOG.SVC_REF, 
    SERVICECATALOG.SVC_DESC, 
    SERVICECATALOG.SDG_ID, 
    STUDYGROUP1.SDG_REF, 
    STUDYGROUP1.SDG_DESC, 
    RECOVERYTXNLEDGER.SVC_PER_ID, 
    PERIOD1.PER_REF, 
    PERIOD1.PER_DESC, 
    RECOVERYTXNLEDGER.SVC_SCN_ID, 
    SCENARIO1.SCN_DESC, 
    RECOVERYTXNLEDGER.SVC_RATE, 
    RECOVERYTXNLEDGER.REC_TRANS_TYPE_ID, 
    RECOVERYTRANSTYPE.REC_TRANS_TYPE_NAME, 
    RECOVERYTXNLEDGER.CUST_ACCT_REF, 
    RECOVERYTXNLEDGER.ORG_REF, 
    ORGANIZATION.ORG_DESC, 
    STUDYGROUP.SDG_ID, 
    STUDYGROUP.SDG_REF, 
    STUDYGROUP.SDG_DESC, 
    RECOVERYTXNLEDGER.VOL_ID, 
    VOLUMECATALOG.VOL_REF, 
    VOLUMECATALOG.VOL_DESC, 
    RECOVERYTXNLEDGER.VOL_PER_ID, 
    PERIOD.PER_REF, 
    PERIOD.PER_DESC, 
    RECOVERYTXNLEDGER.VOL_SCN_ID, 
    SCENARIO.SCN_DESC, 
    RECOVERYTXNLEDGER.VOL_QTY 
    UNION 
    SELECT 
    NULL      AS TXN_ID, 
    NULL      AS REC_PROC_ID, 
    NULL      AS RECORD_PROC_NAME, 
    NULL      AS RECORD_PROC_TYPE_ID, 
    NULL      AS RECORD_PROC_TYPE_NAME, 
    NULL      AS RECORD_PROC_SEQUENCE_NUM, 
    NULL      AS SERVICE_ID, 
    NULL      AS SERVICE_REFERENCE, 
    NULL      AS SERVICE_DESCRIPTION, 
    STUDYGROUP.SDG_ID   AS SERVICE_STUDY_GROUP_ID, 
    STUDYGROUP.SDG_REF   AS SERVICE_STUDY_GROUP_REF, 
    STUDYGROUP.SDG_DESC   AS SERVICE_STUDY_GROUP_DESC, 
    NULL      AS SERVICE_PERIOD_ID, 
    NULL      AS SERVICE_PERIOD_REFERENCE, 
    NULL      AS SERVICE_PERIOD_DESCRIPT, 
    NULL      AS SERVICE_SCENARIO_ID, 
    NULL      AS SERVICE_SCENARIO_DESC, 
    NULL      AS SERVICE_RATE, 
    0       AS TRANS_TYPE_ID, 
    'Financials'    AS TRANS_TYPE_NAME, 
    NULL      AS CUSTOMER_ACCOUNT, 
    Financials.ORG_REF   AS ORGANIZATION_REFERENCE, 
    Organization.ORG_DESC  AS ORGANIZATION_DESCRIPTION, 
    StudyGroup.SDG_ID   AS STUDY_GROUP_ID, 
    StudyGroup.SDG_REF   AS STUDY_GROUP_REFERENCE, 
    StudyGroup.SDG_DESC   AS STUDY_GROUP_DESCRIPT, 
    Sum(Financials.GL_AMOUNT) AS TRANSACTION_AMOUNT, 
    Financials.FIN_ID   AS VOLUME_ID, 
    FINANCIALS.GLACCT_REF  AS VOLUME_REFERENCE, 
    FINANCIALS.GLACCT_DESC  AS VOLUME_DESCRIPTION, 
    Financials.FIN_PER_ID  AS VOLUME_PERIOD_ID, 
    Period.PER_REF    AS VOLUME_PERIOD_REFERENCE, 
    Period.PER_DESC    AS VOLUME_PERIOD_DESCRIPT, 
    Financials.FIN_SCN_ID  AS VOLUME_SCENARIO_ID, 
    Scenario.SCN_DESC   AS VOLUME_SCENARIO_DESCRIPT, 
    NULL      AS VOLUME_QUANTITY 
    FROM (((StudyGroup INNER JOIN Organization ON StudyGroup.SDG_ID = Organization.SDG_ID) 
    INNER JOIN Financials ON Organization.ORG_REF = Financials.ORG_REF) 
    INNER JOIN Scenario ON Financials.FIN_SCN_ID = Scenario.SCN_ID) 
    INNER JOIN Period ON Financials.FIN_PER_ID = Period.PER_ID 
    GROUP BY 
    NULL, 
    NULL, 
    NULL, 
    NULL, 
    NULL, 
    NULL, 
    NULL, 
    NULL, 
    NULL, 
    STUDYGROUP.SDG_ID, 
    STUDYGROUP.SDG_REF, 
    STUDYGROUP.SDG_DESC, 
    NULL, 
    NULL, 
    NULL, 
    NULL, 
    NULL, 
    NULL, 
    0, 
    'Financials', 
    NULL, 
    FINANCIALS.ORG_REF, 
    ORGANIZATION.ORG_DESC, 
    STUDYGROUP.SDG_ID, 
    STUDYGROUP.SDG_REF, 
    STUDYGROUP.SDG_DESC, 
    FINANCIALS.FIN_ID, 
    FINANCIALS.GLACCT_REF, 
    FINANCIALS.GLACCT_DESC, 
    FINANCIALS.FIN_PER_ID, 
    PERIOD.PER_REF, 
    PERIOD.PER_DESC, 
    FINANCIALS.FIN_SCN_ID, 
    SCENARIO.SCN_DESC, 
    NULL

我曾尝试与更换两个字符串：

CASE WHEN StudyGroup.SDG_ID >= 0 THEN 0 ELSE 0 END AS TRANS_TYPE_ID, 
CASE WHEN StudyGroup.SDG_ID >= 0 THEN 'Financials' ELSE 'Financials' END AS TRANS_TYPE_NAME,

，并在GROUP BY：

CASE WHEN StudyGroup.SDG_ID >= 0 THEN 0 ELSE 0 END, 
CASE WHEN StudyGroup.SDG_ID >= 0 THEN 'Financials' ELSE 'Financials' END,

谢谢...

来源

2014-11-03 SoonerArrow

将文字留在群组之外。这个不成立。完全不知道你试图用那些总是返回相同值的case表达式来完成。 – 2014-11-03 19:28:18

我试图让查询工作。我在这里遇到了另一篇文章，提供了他们作为一个工作示例，所以我只是用它来看看我的工作是否也可以。好吧，我把文字拉出来，仍然有相同的错误信息。顺便说一句，我在寻求帮助，而不是批评。 – SoonerArrow 2014-11-03 19:41:59

我会建议使用表别名特别是对于这样的更大的查询。它使阅读更容易看到发生了什么。我调整了你的第二个查询，并添加了一些别名。然后我意识到你在查询中有两个相同的3列，并且你多次将它们分组。这不会影响结果，但它会减少混淆。我猜测问题出在你的第二个查询中，所以我将它分离出来并在将它添加到UNION之前使其工作。

SELECT 
    NULL      AS TXN_ID, 
    NULL      AS REC_PROC_ID, 
    NULL      AS RECORD_PROC_NAME, 
    NULL      AS RECORD_PROC_TYPE_ID, 
    NULL      AS RECORD_PROC_TYPE_NAME, 
    NULL      AS RECORD_PROC_SEQUENCE_NUM, 
    NULL      AS SERVICE_ID, 
    NULL      AS SERVICE_REFERENCE, 
    NULL      AS SERVICE_DESCRIPTION, 
    sg.SDG_ID   AS SERVICE_STUDY_GROUP_ID, 
    sg.SDG_REF   AS SERVICE_STUDY_GROUP_REF, 
    sg.SDG_DESC   AS SERVICE_STUDY_GROUP_DESC, 
    NULL      AS SERVICE_PERIOD_ID, 
    NULL      AS SERVICE_PERIOD_REFERENCE, 
    NULL      AS SERVICE_PERIOD_DESCRIPT, 
    NULL      AS SERVICE_SCENARIO_ID, 
    NULL      AS SERVICE_SCENARIO_DESC, 
    NULL      AS SERVICE_RATE, 
    0       AS TRANS_TYPE_ID, 
    'Financials'    AS TRANS_TYPE_NAME, 
    NULL      AS CUSTOMER_ACCOUNT, 
    f.ORG_REF   AS ORGANIZATION_REFERENCE, 
    o.ORG_DESC  AS ORGANIZATION_DESCRIPTION, 
    sg.SDG_ID   AS STUDY_GROUP_ID, 
    sg.SDG_REF   AS STUDY_GROUP_REFERENCE, 
    sg.SDG_DESC   AS STUDY_GROUP_DESCRIPT, 
    Sum(f.GL_AMOUNT) AS TRANSACTION_AMOUNT, 
    f.FIN_ID   AS VOLUME_ID, 
    f.GLACCT_REF  AS VOLUME_REFERENCE, 
    f.GLACCT_DESC  AS VOLUME_DESCRIPTION, 
    f.FIN_PER_ID  AS VOLUME_PERIOD_ID, 
    p.PER_REF    AS VOLUME_PERIOD_REFERENCE, 
    p.PER_DESC    AS VOLUME_PERIOD_DESCRIPT, 
    f.FIN_SCN_ID  AS VOLUME_SCENARIO_ID, 
    s.SCN_DESC   AS VOLUME_SCENARIO_DESCRIPT, 
    NULL      AS VOLUME_QUANTITY 
    FROM StudyGroup sg 
    INNER JOIN Organization o ON sg.SDG_ID = o.SDG_ID 
    INNER JOIN Financials f ON o.ORG_REF = f.ORG_REF 
    INNER JOIN Scenario s ON f.FIN_SCN_ID = s.SCN_ID 
    INNER JOIN Period p ON f.FIN_PER_ID = p.PER_ID 
    GROUP BY 
    sg.SDG_ID, 
    sg.SDG_REF, 
    sg.SDG_DESC, 
    f.ORG_REF, 
    o.ORG_DESC, 
    f.FIN_ID, 
    f.GLACCT_REF, 
    f.GLACCT_DESC, 
    f.FIN_PER_ID, 
    p.PER_REF, 
    p.PER_DESC, 
    f.FIN_SCN_ID, 
    s.SCN_DESC

另外，我不确定你是否使用UNION，因为你想消除两个查询之间的重复。如果没有，您将通过使用UNION ALL获得更好的性能，因此不必检查重复项。

来源

2014-11-03 20:25:43

谢谢，肖恩。这解决了错误。由于Oracle需要它们，我没有考虑删除所有非表列值。 UNION旨在主要将实际财务数据与研究组，组织，情景和期间结合起来。它是由另一个人提供的，为了使它能够在Oracle中工作，我不得不对其进行调整。然后我被要求把它放在SQL Server中。再次，谢谢你... – SoonerArrow 2014-11-03 20:43:45

哇，我很猜测。我不是甲骨文人。这很奇怪，它需要你通过文字分组。很高兴为你工作。考虑到查询的性质，我有一种感觉，这两组不会返回重复。您可以查看UNION和UNION ALL之间的区别。有时性能差异确实令人震惊。 – 2014-11-03 20:48:42

我会查看UNION ALL，因为查询所在的这个视图最终将查询数十亿条记录。再次感谢... – SoonerArrow 2014-11-04 14:51:41

GROUP BY表达式必须至少包含... UNION查询

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