非void函数错误

Question

我想编译这个程序在C（一CS50在线类），并不断收到以下错误：

fifteen.c：233：1：错误：控制可能到达非void函数结束[-Werror，-Wreturn型] }

我不是问我的代码的逻辑，但更多的寻找，我已经错过了语法错误上一个小时。代码如下。谢谢！

bool move(int tile) 
{ 
    for (int i = 0; i < d - 1; i++){ 

     for (int j= 0; j < d - 1; j++){ 

      if (tile == board[i][j]){ 

       if (board[i+1][j] == tile){ 
        board[i+1][j] = 0; 
        board[i+1][j] = tile; 
        return true; 
             } 
       else if (board [i-1][j] == 0){ 
        board[i-1][j] = tile; 
        board [i-1][j] = 0; 
        return true; 
             } 
       else if (board [i][j+1] == 0){ 
        board[i][j+1] = tile; 
        board [i][j+1] = 0; 
        return true; 
             } 
       else if (board [i][j-1] == 0){ 
        board[i][j-1] = tile; 
        board [i][j-1] = 0; 
        return true; 
             } 
    } 
    return false; 
} 
} 
} 

Answer 1

此错误是说你的方法能到达终点，而不返回的值。这种情况发生在这种情况下，因为你的括号不合适。

尝试以下操作：

bool move(int tile) { 
    for (int i = 0; i < d - 1; i++) { 
      for (int j = 0; j < d - 1; j++) { 
       if (tile == board[i][j]) { 
        if (board[i+1][j] == tile) { 
         board[i+1][j] = 0; 
         board[i+1][j] = tile; 
         return true; 
        } 
        else if (board [i-1][j] == 0){ 
         board[i-1][j] = tile; 
         board [i-1][j] = 0; 
         return true; 
        } 
        else if (board [i][j+1] == 0){ 
         board[i][j+1] = tile; 
         board [i][j+1] = 0; 
         return true; 
        } 
      } 
      else if (board [i][j-1] == 0){ 
       board[i][j-1] = tile; 
       board [i][j-1] = 0; 
       return true; 
      } 
     } 
    } 
    return false; 
}