一种选择是,通过重复使用不同的子类的视图。 Razor甚至会根据发送给视图的具体类型识别属性并填充html。
子类只是解决方案的一部分。第二部分是表单发布后需要发生的模型绑定。 您可以通过创建一个自定义模型联编程序来解决此问题,如其中一个注释中所述。 另一个方法是调整表单的动作,以便将表单发布到可处理正确视图模型类型的操作。具有多个操作的优点是,对操作实施定制验证变得微不足道。
使用多个操作可能不是最优雅的解决方案。我不确定是否有任何不良副作用。
下面是一个示例视图模型:
// This is the base class declared as the view's @model
// This one would have all the common validations
public class TestViewModel
{
public string ModelType { get; set; }
public virtual string Prop1 { get; set; }
public virtual string Prop2 { get; set; }
public virtual string Prop3 { get; set; }
}
public class TestViewModel1 : TestViewModel
{
[Required]
public override string Prop1 { get; set; }
}
public class TestViewModel2 : TestViewModel
{
[Required]
public override string Prop1 { get; set; }
[Required]
public override string Prop2 { get; set; }
}
而且,所述控制器:
public class TestController : Controller
{
// GET: Test
public ActionResult Edit(string modelType)
{
if (modelType == "1") return View(new Models.TestViewModel1() {ModelType = "1"});
if (modelType == "2") return View(new Models.TestViewModel2() {ModelType = "2" });
return View(new Models.TestViewModel() { ModelType = "" });
}
[HttpPost]
public ActionResult Edit(Models.TestViewModel model)
{
if (model.Prop1 == null) ModelState.AddModelError("Prop1", "Please type something");
if (ModelState.IsValid) return RedirectToAction("Edit");
return View(model);
}
[HttpPost]
public ActionResult Edit1(Models.TestViewModel1 model)
{
if (model.Prop1 == null || !model.Prop1.Contains("1")) ModelState.AddModelError("Prop1", "Please type at least one character 1");
if (ModelState.IsValid) return RedirectToAction("Edit", new { modelType = "1" });
return View("Edit", model);
}
[HttpPost]
public ActionResult Edit2(Models.TestViewModel2 model)
{
if (model.Prop2 == null || !model.Prop1.Contains("2")) ModelState.AddModelError("Prop2", "Please type at least one character 2");
if (ModelState.IsValid) return RedirectToAction("Edit", new { modelType = "2"});
return View("Edit", model);
}
}
和视图(看@using(Html.BeginForm ..):
@model WebApplication1.Models.TestViewModel
@{
Layout = null;
}
@Scripts.Render("~/bundles/jquery")
@Scripts.Render("~/bundles/jqueryval")
@using (Html.BeginForm("Edit" + Model.ModelType, "Test", new {Model.ModelType}))
{
@Html.AntiForgeryToken()
<div class="form-horizontal">
<h4>TestModel</h4>
<hr />
@Html.ValidationSummary(true, "", new { @class = "text-danger" })
@DateTime.Now.ToString("o")
<br/>
@Html.LabelFor(m => m.ModelType)
@Html.DisplayFor(m => m.ModelType)
<hr />
<div class="form-group">
@Html.LabelFor(model => model.Prop1, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.Prop1, new { htmlAttributes = new { @class = "form-control" } })
@Html.ValidationMessageFor(model => model.Prop1, "", new { @class = "text-danger" })
</div>
</div>
<div class="form-group">
@Html.LabelFor(model => model.Prop2, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.Prop2, new { htmlAttributes = new { @class = "form-control" } })
@Html.ValidationMessageFor(model => model.Prop2, "", new { @class = "text-danger" })
</div>
</div>
<div class="form-group">
@Html.LabelFor(model => model.Prop3, htmlAttributes: new { @class = "control-label col-md-2" })
<div class="col-md-10">
@Html.EditorFor(model => model.Prop3, new { htmlAttributes = new { @class = "form-control" } })
@Html.ValidationMessageFor(model => model.Prop3, "", new { @class = "text-danger" })
</div>
</div>
<div class="form-group">
<div class="col-md-offset-2 col-md-10">
<input type="submit" value="Save" class="btn btn-default" />
</div>
</div>
</div>
}
<div>
@Html.ActionLink("Back to List", "Index")
</div>
一种选择是使用具有条件验证属性的单个模型/视图/动作方法,例如e使用[foolproof](http://foolproof.codeplex.com/)'[RequiredIf]'或类似的类型属性。另一种方法是对模型使用“基本”类/接口,然后创建一个自定义的'ModelBinder'来在POST方法中生成具体类。 –
太棒了!多谢你们!由于时间紧迫,我走了一条万无一失的路线,但这些都是很好的建议。 – bigtri