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我试图从客户端(Ionic框架)发送图像到我的Python后端(烧瓶)。出于某种原因,我不断收到错误代码3,我知道这是一个连接错误,但我不知道为什么。发送图像到Python后端 - 科尔多瓦文件传输
客户端代码(AngularJS):
$scope.submit = function() {
if($scope.details.title === '' || $scope.details.price === '' || $scope.details.description === ''
|| $scope.details.category === '') {
ionicSuperPopup.show("Error!", "Fill out the appropriate fields!", "error");
} else if($scope.size !== 2) {
ionicSuperPopup.show("Error!", "You need to upload at least two images.", "error");
} else {
/* Post item to server, wait for success, and present success post. */
//ItemFactory.addItem($scope.details);
var url = 'http://127.0.0.1:5000/api/item/addItem';
var name = $scope.details.images[0];
var options = new FileUploadOptions();
options.fileKey = 'image',
options.fileName = name,
options.chunkedMode = false,
options.mimeType = 'image/jpg',
options.params = { 'filename': name };
options.headers = {
Connection: "close"
};
var ft = new FileTransfer();
ft.upload($scope.list[0], encodeURI(url), win, fail, options);
} /* End of 'else' */
} /* End of 'submit' */
$ scope.list [0]包含拍摄的照片的imageURI。
后端代码:
from flask_restful import reqparse, Resource
class Item(Resource):
parser = reqparse.RequestParser(bundle_errors=True) #All arguments must be present
def post(self):
Item.parser.add_argument('image', required=True, help="You need images.")
args = Item.parser.parse_args()
print("We have: {}".format(args))
有什么,我做错了吗?我觉得我已经覆盖了一切,但我不明白为什么我有一个错误代码3.感谢您的帮助!
只是好奇,你为什么要使用连接关闭HTTP标头? –
这是一个试图解决这个问题。但我实际上找出了什么是错的。您需要: Item.parser.add_argument('file',required = True,help =“您需要图像。”,type = werkzeug.datastructures.FileStorage,location ='files') – Zain