“缺少右括号”MySQL错误

Question

我试图运行一个查询，它会将四舍五入的平均值显示为两位小数。这是我的代码，我不知道为什么我不断收到错误。

SELECT 
    ROUND(AVG (Scholarship, 2)) AS 'Average Scholarships' 
FROM 
    student; 

Answer 1

SELECT ROUND(AVG (Scholarship), 2) AS 'Average Scholarships' FROM student; 

Answer 2

你传入Scholarship, 2到AVG功能，只期待一个参数。

你的意思做的是通过AVG (Scholarship)和2到ROUND，像这样：

SELECT ROUND(AVG (Scholarship), 2) AS 'Average Scholarships' FROM student;