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我已经看了这些例子到目前为止Multiplying two 2D arrays {这是C++所以不知道如何有用的ti将为php} JSON encode multiplies arrays as single array {尽管php代码它不乘以两个数组} Multiplying two arrays in php {这几乎是我想要做的,但解决方案不工作,所以不知道如果它的解决方案或它是不需要的}将两个数组从MYSQL数据乘到一个新的PHP数组中
基本上我想要做的是,拿两从一个mysql数据库生成的数组到另一个数组,总数是两个mysql数组数组的乘积。
我已经尝试了很多不同的方式,如下所列,目前为止没有运气。
<?php
//Database connection
$db=mysqli_connect("***","***","***","***") or die(mysqli_error($db));
//This is to test if there is a php scripting error ie white screen etc if no results are displayed
echo "test";
//SQL Statements
$sql4="SELECT * FROM invoicequote";
$sql5="SELECT SUM(unitprice*units) AS total FROM invoicequote";
//Query database for results
$result4=mysqli_query($db,$sql4) or die(mysqli_error($db));
$result5=mysqli_query($db,$sql5) or die(mysqli_error($db));
//Arrays of services performed and prices
$service=array();
$workdone=array();
$unitprice=array();
$units=array();
$total=array();
//While loop for invoice or quote information
while($num = mysqli_fetch_assoc($result4))
{
$service[]=$num['servicesused'];
$workdone[]=$num['serviceworkdone'];
$unitprice[]=$num['unitprice'];
$units[]=$num['units'];
//$total[]=($unitprice*$units);
}
//Also tried $total[]=($unitprice[]*$units[]); but this gave a white screen i suspect because there was no index supplied
//Put total into array by multiplying the unit price and number of units
/*
for ($unitprice as $price && $unit as $u)
{
$total=array($price*$u);
echo $total[0];
} //This gives a white screen it appears to be a infinite loop
*/
//use mysql to do the calculations before it comes out into php
/*
while($num = mysqli_fetch_array($result5))
{
$total[]=$num['total'];
echo $total[0]; //this gives the total off all prices rather than individuals prices
}
*/
//putting results into a array
$arr=count($units);
for($i=0;$i<$arr;$i++)
{
$total[]=$unitprice[$x]*$unit[$x]; //this gives a white screen as well
}
//Display the results
$arrlength=count($units);
//This is the prefer way to display the results but i am open to anything that works
for($x=0;$x<$arrlength;$x++)
{
echo $total[$x];
}
mysqli_close($db);
?>
数据库中的信息删除
我怀疑我试图让PHP做实际的计算,这是问题的为每个变量的数据显示正常,只有当我尝试繁殖方式他们是否会成为问题。
这个问题有很多代码在里面。如果你能够通过解释代码行的位置来帮助提问者,并且提请注意这条线与提问者之间的区别,那将会很好。 –
抱歉,迟到的回应,当最初尝试它,它从来没有工作,但似乎我正在测试的代码页已成为破碎或缓存在错误的状态,当我添加它住另一个单独的测试页它工作很好,也似乎我在我的一个例子中得到了更多,但我忘了用我替换x – andy