使用WITH的SQL查询common_table_expression在Codeigniter中失败，但在SQL Studio中失败

Question

我在MS SQL Management Studio中为SQL Server 2012创建了一个查询，该查询使用common_table_expression自加入表。它在MS SQL Studio中正常工作，但在Codeigniter中没有结果或返回错误。

查询：

WITH rows AS 
    (
    SELECT *, ROW_NUMBER() OVER (ORDER BY u.[PatientID], u.[CreateDate]) AS rn 
    FROM (
     SELECT a.[PatientID], a.[BGValue], a.[CreateDate], a.[HospitalUnit], 'MSHA' as 'Hospital', h.[system_name], f.[facility_code], f.[facility_name], 'IV' as 'Treatment' 
     FROM [Analytics].[dbo].[MSHA_IVTreatment] a 

     JOIN [Analytics].[dbo].[MSHA_Patients] p 
     ON p.[PatientID] = a.[PatientID] 

     JOIN [Analytics].[dbo].[Facilities] f 
     ON f.[facility_code] = p.[facility_code] 

     JOIN [Analytics].[dbo].[Hospitals] h 
     ON f.[hospital] = h.[hospital] 

     WHERE a.[CreateDate] BETWEEN '2013-05-01' AND '2013-05-31' 

     UNION ALL 

     SELECT a.[PatientID], a.[BGValue], a.[CreateDate], a.[HospitalUnit], 'MSHA' as 'Hospital', h.[system_name], f.[facility_code], f.[facility_name], 'SubQ' as 'Treatment' 
     FROM [Analytics].[dbo].[MSHA_SubQTreatment] a 

     JOIN [Analytics].[dbo].[MSHA_Patients] p 
     ON p.[PatientID] = a.[PatientID] 

     JOIN [Analytics].[dbo].[Facilities] f 
     ON f.[facility_code] = p.[facility_code] 

     JOIN [Analytics].[dbo].[Hospitals] h 
     ON f.[hospital] = h.[hospital] 

     WHERE a.[CreateDate] BETWEEN '2013-05-01' AND '2013-05-31' 
     ) u 
    ) 
SELECT mc.[PatientID], mc.[BGValue], mc.[CreateDate], mc.[Hospital], mc.[system_name] as 'System', mc.[facility_code], mc.[facility_name], mc.[HospitalUnit], DATEDIFF(second, mp.[CreateDate], mc.[CreateDate])/60 as 'Interval', mc.[Treatment] 
FROM rows mc 
JOIN rows mp 
ON  mc.rn = mp.rn + 1 and mc.[PatientID] = mp.[PatientID] 
ORDER BY mc.[CreateDate] ASC; 

当我将它放入一个变量，并尝试检索结果在笨不返回任何结果：

$result = $this->db->query($query); 

CI_DB_sqlsrv_result Object 
(
[conn_id] => Resource id #30 
[result_id] => Resource id #41 
[result_array] => Array 
    (
    ) 

[result_object] => Array 
    (
    ) 

[custom_result_object] => Array 
    (
    ) 

[current_row] => 0 
[num_rows] => -1 
[row_data] => 
) 

我曾试图把查询的事务，但得到了同样的结果。

任何有识之士非常感谢。

Answer 1

这可能是有益的你 -

;WITH [rows] AS 
(
    SELECT 
      a.[PatientID] 
      , a.[BGValue] 
      , a.[createdate] 
      , a.[HospitalUnit] 
      , Hospital = 'MSHA' 
      , h.[system_name] 
      , f.[facility_code] 
      , f.[facility_name] 
      , u.Treatment 
      , rn = ROW_NUMBER() OVER (ORDER BY u.[PatientID], u.[createdate]) 
    FROM (
      SELECT 
       PatientID 
       , BGValue 
       , createdate 
       , HospitalUnit 
       , Treatment = 'IV' 
      FROM dbo.MSHA_IVTreatment 
      WHERE createdate BETWEEN '20130501' AND '20130531' 

      UNION ALL 

      SELECT 
       PatientID 
       , BGValue 
       , createdate 
       , HospitalUnit 
       , Treatment = 'SubQ' 
      FROM dbo.MSHA_SubQTreatment 
      WHERE createdate BETWEEN '20130501' AND '20130531' 
    ) a 
    JOIN [dbo].[MSHA_Patients] p ON p.[PatientID] = a.[PatientID] 
    JOIN [dbo].[Facilities] f ON f.[facility_code] = p.[facility_code] 
    JOIN [dbo].[Hospitals] h ON f.[Hospital] = h.[Hospital] 
) 
SELECT 
     mc.[PatientID] 
    , mc.[BGValue] 
    , mc.[createdate] 
    , mc.[Hospital] 
    , [System] = mc.[system_name] 
    , mc.[facility_code] 
    , mc.[facility_name] 
    , mc.[HospitalUnit] 
    , [Interval] = DATEDIFF(SECOND, mp.[createdate], mc.[createdate])/60 
    , mc.[Treatment] 
FROM [rows] mc 
JOIN [rows] mp ON mc.rn = mp.rn + 1 AND mc.[PatientID] = mp.[PatientID] 
ORDER BY mc.[createdate];