0
我有一个查询,我创建了哪个输出项目以及谁在呈现项目。我的问题是,我试图将演示者分组到项目ID,以便列出项目ID下的演示者并且不多次包含它。TSQL组按问题导致重复
这里是我的查询:
DECLARE @agendaID AS INT = '23';
SELECT
(SELECT att.empID,
emp.firstName,
emp.lastName,
emp.ntid
FROM dbo.BS_ProjectReview_Attendees AS att
LEFT OUTER JOIN
dbo.EmployeeTable AS emp
ON att.empID = emp.EmpID
WHERE att.agendaID = @agendaID
FOR XML PATH ('attendee'), TYPE, ELEMENTS, ROOT ('attendees')),
(SELECT pres.intID,
int.intTitle,
(SELECT emp.firstName,
emp.lastName,
emp.ntid
FROM dbo.EmployeeTable AS emp
WHERE emp.EmpID = pres.empID
FOR XML PATH ('presenter'), TYPE, ELEMENTS, ROOT ('presenters'))
FROM dbo.BS_ProjectReview_ProjectPresenters AS pres
INNER JOIN dbo.BS_Initiatives AS int
ON pres.intID = int.intID
WHERE pres.agendaID = @agendaID
GROUP BY int.intID <----- ISSUE IS HERE
FOR XML PATH ('project'), TYPE, ELEMENTS, ROOT ('projects'))
FOR XML PATH ('data'), TYPE, ELEMENTS, ROOT ('root');
这里是我的XML输出:
<root>
<data>
<attendees>
<attendee>
<empID>1234</empID>
<firstName>Mike</firstName>
<lastName>Smith</lastName>
<ntid>msmith</ntid>
</attendee>
</attendees>
<projects>
<project>
<intID>202</intID>
<intTitle>Infrastructure Expansion</intTitle>
<presenters>
<presenter>
<firstName>Bob</firstName>
<lastName>Jones</lastName>
<ntid>bjones</ntid>
</presenter>
</presenters>
</project>
<project>
<intID>202</intID>
<intTitle>Infrastructure Expansion</intTitle>
<presenters>
<presenter>
<firstName>User 1</firstName>
<lastName>Last 1</lastName>
<ntid>ulast1</ntid>
</presenter>
</presenters>
</project>
</projects>
</data>
</root>
下面是所需的输出:
<root>
<data>
<attendees>
<attendee>
<empID>1234</empID>
<firstName>Mike</firstName>
<lastName>Smith</lastName>
<ntid>msmith</ntid>
</attendee>
</attendees>
<projects>
<project>
<intID>202</intID>
<intTitle>Infrastructure Expansion</intTitle>
<presenters>
<presenter>
<firstName>Bob</firstName>
<lastName>Jones</lastName>
<ntid>bjones</ntid>
</presenter>
<presenter>
<firstName>User 1</firstName>
<lastName>Last 1</lastName>
<ntid>ulast1</ntid>
</presenter>
</presenters>
</project>
</projects>
</data>
</root>
应列出下两个主持人但是它的复制方法与intID
相同。
我收到一个错误的group by子句,因为它没有包含在一个聚合函数中,并且希望我包含pres.empID
,但它不会使它唯一,因为它们都是不同的。
任何想法?
很确定你需要@语法。见http://stackoverflow.com/questions/8483936/tsql-for-xml-explicit – Paparazzi
这篇文章似乎并没有涉及到我的问题。问题在于我在问题中确定的小组小句。 – SBB
为什么不发布期望的输出 – Paparazzi