我想获取Sample的项目名称。它应该是self.args因为我的urls.py看起来像这样(有很多网址,所以我将只发布重要的):Django在ListView中为空self.args时<pk>在urls.py
项目/ urls.py
app_name = 'projects'
urlpatterns = [
url(r"^$", ProjectListView.as_view(), name="projects_list"),
url(r"^(\w+)/robjects/", include("robjects.urls")),
url(r"^(\w+)/tags/$", TagsListView.as_view(), name="tag_list"),
...
]
robjects /网址的.py
app_name="robjects"
urlpatterns = [
...
url(r'^(?P<pk>[0-9]+)/samples/', include("samples.urls")),
]
样品/ urls.py
app_name="samples"
urlpatterns = [
url(r'^list/$', SampleListView.as_view(), name='sample_list_view'),
url(r'^create/$', SampleCreateView.as_view(), name='sample_create_view'),
url(r'^(?P<sample_id>[0-9]+)/update/$', SampleUpdateView.as_view(), name='sample_update'),
url(r'^(?P<sample_id>[0-9]+)/delete/$', SampleDeleteView.as_view(), name='sample_delete'),
]
我想PROJECT_NAME,这是幻灯的 '(\ w +)' 的一部分CTS/urls.py。为此,我在samples/views.py中编写了该代码。我试图做project_name = self.args [0]但我的参数是空的。
类SampleListView(ListView控件): 模型=样品 TEMPLATE_NAME = “样品/ samples_list.html”
def get(self, request, *args, **kwargs):
"""A base view for displaying a list of objects."""
# check if project exists
try:
pk = kwargs['pk']
robject = Robject.objects.get(id=pk)
# add project to view attributes
self.robject = robject
except Robject.DoesNotExist:
raise Http404
print(self.args) # it should be a project name here
return super(SampleListView, self).get(request, *args, **kwargs)
def get_queryset(self, *args, **kwargs):
"""
Overwrite orginal qs and add filtering by robject
"""
# original queryset
qs = super().get_queryset(*args, **kwargs)
print('args, ',self.args)
print('kwargs', self.kwargs)
pk = self.kwargs['pk']
robject = Robject.objects.get(id=pk)
return qs.filter(robject=self.robject)
这是输出:
args, ()
kwargs {'pk': '27'}
我想要筛选我的QS robject_id和通过project_name,为robject_id它工作正常。我不知道如何获取project_name进行过滤。
此外,我不得不说,在标签(“不包括在urls”)我做了self.argss [0],它的工作原理,但只是形成标签ListView。下面
代码:
class TagsListView(LoginRequiredMixin, ListView):
model = Tag
template_name = "tags/tag_list.html"
def get(self, request, *args, **kwargs):
"""A base view for displaying a list of objects."""
# check if project exists
try:
project = Project.objects.get(name=args[0]) # it works fine
# add project to view attributes
self.project = project
except Project.DoesNotExist:
raise Http404
return super(TagsListView, self).get(request,*args, **kwargs)
这是我发现:
当我定义我的网址这样的:
url(r"^(\w+)/robjects/samples/$", SampleListView.as_view(), name='sample_list_view'),
所有worrks。在我的参数表是PROJECT_NAME,我可以通过self.args抓住它[0]
但当我添加到我的ARG游戏空,
url(r"^(\w+)/robjects/(?P<pk>[0-9]+)/samples/$", SampleListView.as_view(), name='sample_list_view'),
当我定义了两个kwargs像这样的:
url(r"^(?P<project_name>[\w\-]+)/robjects/(?P<pk>[0-9]+)/samples/list/$",SampleListView.as_view(), name='sample_list_view'),
ARGS空 - 我所期待的,kwargs都是确定并传递给视图
它是Django的bug还是有任何方式使用self.args?他们是否被kwargs压倒了?
感谢您的帮助!