-1
display_list = ['display','screen']
water_list = ['wet','water','sink','Toilet']
crack_list = ['cracked','broke','broken']
for item in display_list:
if item in problem:
f_display = True
for item in display_list and crack_list:
if item in problem:
f_screencrack = True
for item in water_list:
if item in problem:
f_water = True
elif f_screencrack == True:
print('You may need to replace your screen.')
print('Note that if the crack is too heavy, you may need a new phone.')
,我想我的程序能够显示不同的答案,如果用户的答案可以在这两个display_list
和crack_list
被发现,但我不知识。察看项目仅在一个列表或蟒蛇多者