我有点迷路,我试图放置一个链接返回到“窗体”页面或“主页”页面为每个错误消息,当用户提交表单。当用户成功提交表单时,它会将链接返回到表单页面或主页。基本上我想修复链接返回到表单或主页。谢谢你们,请让我知道我能做什么或指导我。修复链接返回到表单或主页
这也是迄今为止该进程的一部分我的代码:
<?php
//
//umask(0007)
//mkdir($newdir, 02770);
//$filename = "../../data/status.txt";
$errors = array();
$permissionsArray = (isset($_POST['permission']) ? $_POST['permission'] : null);
if (isset($_POST["statuscode"]))
{
$statusCode = $_POST["statuscode"];
$patternCode = "/^S[0-9]{4}$/";
if (preg_match($patternCode, $statusCode))
{
$ans = "";
$length = strlen($statusCode);
echo $statusCode . "<br />";
}
}
else
{
array_push($errors, "Please fill in Status Code as they are mandatory field");
}
if (isset ($_POST["status"]))
{
$status = $_POST["status"];
$pattern = "/^[a-zA-Z0-9\s\.,!?]*$/";
if (preg_match($pattern, $status))
{
echo $status . "<br />";
}
}
else
{
array_push($errors, "<b>Error:</b> Please fill in Status as they are mandatory field!");
}
if (isset ($_POST["share"]))
{
$shareButton = $_POST["share"];
echo $shareButton . "<br />";
}
else
{
//Not possible unless in exceptional circumstances
array_push($errors, "Please choose a share");
}
if (!isset($_POST["date"]))
{
$date = date("d/m/y");
echo $date . "<br />";
} else {
$date = $_POST["date"];
}
if (isset($permissionsArray))
{
foreach($permissionsArray as $permission){
echo $permission . "<br />";
}
}
if(isset($statusCode, $status))
{
if(empty($statusCode) || empty($status))
{
array_push($errors, "Please fill in the required part!");
}
if (0 === strlen($statusCode > 5 || $statusCode < 5))
{
array_push($errors, "<b>Error:</b> You characters length is either less or more than 5 characters<br/>");
}
if (0 === preg_match("/\S+/", $statusCode))
{
array_push($errors, "<b>Error:</b> You forgot to fill in Status Code!<br/>");
}
if (0 === preg_match("/\S+/", $status))
{
array_push($errors, "<b>Error:</b> You forgot to fill in the Status! <br/>");
}
if (0 === preg_match($patternCode, $statusCode))
{
array_push($errors, "<b>Error:</b> please make sure that the first letter in Status Code is uppercase 'S' following by 4 numbers. <br/>");
}
if (0 === preg_match($pattern, $status))
{
array_push($errors, "<b>Error:</b> Please make sure to avoid symbols other than \",.?!\" <br/>");
}
}
if (isset($errors))
{
foreach ($errors as $error)
{
echo '<strong>', $error, '</strong>';
}
}
?>
在表单打印代码之前添加此错误消息代码。 –
当出现错误时,不要让它们返回。将表单提交给自己,在发布数据时对其进行验证,然后在表单上方显示错误,将$ _POST中的所有值放在其各自的表单字段中。当表格按照你描述你的方式工作时,我会受到皇室的愤怒。我失去了我输入的数据(主要问题),并且表单中还有一个额外的步骤,用户通常不喜欢。只需内联。在表单上方有一个'if(!empty($ _ POST ['some_field'])){//验证码}'。 – FluffyJack