获取在线用户的名称

正如我在之前的文章中提到的，我们正在为特定网站创建聊天。现在这个聊天将不得不检索在线用户的名字，并且一旦一个用户退出聊天，就会自动更新。我们能够通过使用PHP的孤独和现在我们正在尝试使用jQuery来避免经常refreshing.so创建至今这一点，这是我们所拥有的：获取在线用户的名称

 <?php 
    session_start();  //Configuation 
    ?> 

    <link rel="stylesheet" type="text/css" href="http://www.pinoyarea.com/videochat/css/winterblues.css"> 

    <?php 

     $name = $_SESSION['username']; 
     $room = $_SESSION['room']; 
     $user = $_SESSION['user']; 
     if($name == NULL || $room == NULL || $user = NULL) 
     { 
      echo "<script>window.location = 'http://www.pinoyarea.com/index.php?p=member/signup';</script>"; 
     } 
    include "connect.php"; 

    $timeoutseconds = 60; // length of session, 20 minutes is the standard 
    $timeoutseconds_idle = 30; 
    $timestamp=time(); 
    $timeout=$timestamp-$timeoutseconds; 
    $timeout_idle=$timestamp-$timeoutseconds_idle; 
    $PHP_SELF = $_SERVER['PHP_SELF']; 
    if (!empty($_SERVER["HTTP_CLIENT_IP"])) 
    { 
     //check for ip from share internet 
     $ip = $_SERVER["HTTP_CLIENT_IP"]; 
    } 
    elseif (!empty($_SERVER["HTTP_X_FORWARDED_FOR"])) 
    { 
     // Check for the Proxy User 
     $ip = $_SERVER["HTTP_X_FORWARDED_FOR"]; 
    } 
    else 
    { 
     $ip = $_SERVER["REMOTE_ADDR"]; 
    } 
    $temp = @mysql_query("SELECT * FROM useronline WHERE online_name='$name' AND online_user='$user' AND online_room='$room'"); 
     $rowie = @mysql_num_rows($temp); 
    // Add this user to database 
     $loopcap = 0; 
     while ($loopcap<3){ 
     if($rowie == 0 AND $name != NULL) 
     { 
     @mysql_query("insert into useronline values('$timestamp','$ip','$PHP_SELF','$name','$room','$user')"); 
     } 
     else 
     { 
     } // in case of collision 
     $timestamp = $timestamp+$ip{0}; $loopcap++; 
     } 

     // Delete users that have been online for more then "$timeoutseconds" seconds 
      mysql_query("delete from useronline where timestamp<$timeout"); 

     //Modified 

     // Select users online 
     $result = @mysql_query("select distinct online_name from useronline"); 
     $result2 = @mysql_query("SELECT distinct online_name FROM useronline WHERE online_room='$room'"); 
     $user_count = @mysql_num_rows($result2); 
     mysql_free_result($result); 
     @mysql_close(); 


    // Show all users online 
    echo '<table name="tableonline" width="180px">'; 
    if ($user_count==1) 
     { 
    echo '<tr><th>'; 
    echo '<font size="1px" style="font-family:arial;"><strong>'.$user_count.' Toozer Online</th></tr>'; 
     } 
     else 
     { 
    echo '<tr><th>'.$user_count.' Toozers Online</strong></font></th></tr></table>'; 
     } 

    echo "</table><br /><table width='180px'>"; 
    while($cell = mysql_fetch_array($result2)) 
    { 
    $timestamping = $cell["timestamp"]; 
    if($timestamping >= $timeout_idle && $timestamping < $timeout) 
    { 
     $src = "http://www.pinoyarea.com/images/videochat/user-offline.png"; 
    } 
    else 
    { 
    $src = "http://www.pinoyarea.com/images/videochat/user-online.png"; 
    } 
     echo '<tr><td><img src="'.$src.'"/><font size="1px" style="text-decoration:none;font-family:tahoma;"></td><td>'.$cell["online_name"].'</font>'; 
     echo '<br /></td></tr>'; 
    } 
    echo '<table>'; 

    ?> 
    <script type="text/javascript" src="http://code.jquery.com/jquery-1.4.2.min.js"> </script> 
    <script> 
    $(document).ready(function() { 
    $("#tableonline").load("online_users.php"); 
    var refreshId = setInterval(function() { 
    $("#tableonline").load('online_users.php?randval='+ Math.random());}, 3000); 
    }); 
    </script> 

    //<META HTTP-EQUIV="Refresh" CONTENT="10">

来源

2011-11-04 jamie mariz labuguen

那么....有什么问题？ –

您是否想要评论该元刷新标记？如果是这样，'/ /'不会在html中工作，你需要'' –

问题是，一旦用户下线，列表不会更新。这意味着离线用户的名字仍然出现在在线用户列表中。我们试图在用户离线时自动更新在线用户列表。 –