PHP在foreach循环中替换多个字符串

Question

我正在抓取一个页面的源代码，其中包含大量列在列中的PDF链接（文件）。 simple_php_dom.php

TALB20170826D-$A$$-RA11.pdf 
TAP$20170826D-$A$$-RA11.pdf 
TASD20170826D-$A$$-RA11.pdf 
TAUA20170826D-$A$$-RA11.pdf 
TAUB20170826D-$A$$-RA11.pdf 
TAUC20170826D-$A$$-RA11.pdf 
TAUD20170826D-$A$$-RA11.pdf 
TBTP20170826D-$A$$-RA11.pdf 
TCBY20170826D-$A$$-RA11.pdf 

我需要foreach循环

foreach($html->find('a') as $element) 
echo $element->href; 

例如TALB是奥尔巴尼的缩写在其中重命名，TAP是亚太地区等的缩写。

我有一个与缩写相对应的名称列表，但不确定如何在循环内重命名它们？任何帮助将不胜感激！

Answer 1

你可以把替换的列表中数组：

<?php  
/* 
$list = []; 
$list[] = "TALB20170826D-\$A$$-RA11.pdf"; 
$list[] = "TAP$20170826D-\$A$$-RA11.pdf"; 
$list[] = "TASD20170826D-\$A$$-RA11.pdf"; 
$list[] = "TAUA20170826D-\$A$$-RA11.pdf"; 
$list[] = "TAUB20170826D-\$A$$-RA11.pdf"; 
$list[] = "TAUC20170826D-\$A$$-RA11.pdf"; 
$list[] = "TAUD20170826D-\$A$$-RA11.pdf"; 
$list[] = "TBTP20170826D-\$A$$-RA11.pdf"; 
$list[] = "TCBY20170826D-\$A$$-RA11.pdf"; 
*/ 
$list = $html->find('a'); 
$abbr = [ 
    "TALB", 
    "TAP", 
    // ... 
]; 
$replacements = [ 
    "ALBANY", 
    "Asia Pacific", 
    // ... 
]; 
foreach ($list as &$el) { 
    $el->href = str_replace($abbr, $replacements, $el->href); 
} 

Demo

或者，让他们都在同一个关联数组（顺序并不重要，缺少的项目只是不会替换，没有错误）：

<?php  
/*$list = []; 
$list[] = "TALB20170826D-\$A$$-RA11.pdf"; 
$list[] = "TAP$20170826D-\$A$$-RA11.pdf"; 
$list[] = "TASD20170826D-\$A$$-RA11.pdf"; 
$list[] = "TAUA20170826D-\$A$$-RA11.pdf"; 
$list[] = "TAUB20170826D-\$A$$-RA11.pdf"; 
$list[] = "TAUC20170826D-\$A$$-RA11.pdf"; 
$list[] = "TAUD20170826D-\$A$$-RA11.pdf"; 
$list[] = "TBTP20170826D-\$A$$-RA11.pdf"; 
$list[] = "TCBY20170826D-\$A$$-RA11.pdf";*/ 
$list = $html->find('a'); 
$abbr = [ 
    "TALB" => "ALBANY", 
    "TAP" => "Asia Pacific", 
]; 
foreach ($list as &$el) { 
    $el->href = strtr($el->href, $abbr); 
} 

Demo

或者使用array_map()，也许你会发现它有点清洁：

$list = array_map(function($el) use($abbr) { 
    return strtr($el, $abbr); 
}, $list);