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我已经得到了这段代码,它在Html代码的div上添加了YouTube频道($ _POST)的视频(和视频信息),并且我想在Youtube中播放视频播放器后点击一个元素:Youtube API loadVideoByUrl()函数
var args= "url="+urlchaine;
xhr_object.open("POST", "traitement.php", true);
xhr_object.onreadystatechange = function() {
if(xhr_object.readyState == 4) {
eval(xhr_object.responseText);
}
return xhr_object.readyState;
}
xhr_object.setRequestHeader("Content-type", "application/x-www-form-urlencoded");
xhr_object.send(args);
traitement.php:
<?php
if (isset($_POST["url"]) && !empty($_POST["url"]))
$urlchaine = $_POST["url"];
else
$urlchaine = null;
$stringresult = str_replace("http://www.youtube.com/user/", "",$urlchaine);
require_once "Zend/Loader.php";
Zend_Loader::loadClass('Zend_Gdata_YouTube');
$yt = new Zend_Gdata_YouTube();
$videoFeed = $yt->getVideoFeed('http://gdata.youtube.com/feeds/users/...');
if ($stringresult != null){
echo "var mydiv = document.getElementById('vids');";
echo "var newcontent = document.createElement('div');";
foreach ($videoFeed as $v): $thumbs = $v->getVideoThumbnails();
echo "newcontent.innerHTML = '...'";
echo "mydiv.appendChild(newcontent.firstChild);";
endforeach;
echo "img_videos.addEventListener('click',function() {
$('#ytplayer_footer').fadeIn('normal');
var idvideo = this.getAttribute('idvideo');
var ytplayer = document.getElementById('ytplayer');
ytplayer.loadVideoByUrl('...'); // ****** Here the problem
ytplayer.playVideo();
},false);";
?>
而且我有这样的错误:对象#有没有方法 'loadVideoByUrl' 什么是错在我的代码?
您是否改变了这个问题? –
错误的复制/粘贴,对不起,我编辑了代码。 – user3185672
我该怎么做?我试图在loadVideoByUrl调用之前调用onTubePlayerReady()函数,但它不会改变任何内容。 – user3185672