python：将数字转换为单词

Question

我正在尝试编写一个将数字转换为单词的代码，最多可达999兆。这是我的代码到目前为止。它工作到119，但之后事情变得混乱。我不能使用append或枚举。我被困在如何打印更大的数字;我将如何格式化一个数字，如978,674,237,105？

NUMBERS = ["zero", "one", "two","three","four","five","six","seven","eight","nine", 
       "ten","eleven","twelve","thirteen","fourteen","fiveteen","sixteen", 
       "seventeen","eightteen","nineteen"] 

TENS = ["", "", "twenty", "thirty", "forty", "fifty", "sixty", "seventy", "eighty", 
      "ninety"] 

HUNNITS = ["","hundred","thousand","million","billion","trillion"] 

n = eval(input("What is the number the you want to convert? ")) 

def convert(): 
    if n >= 20: 
     tens = n // 10 
     units = n % 10 

     if units != 0: 
      result = TENS[tens] + "-" + NUMBERS[units] 
     else: 
      result = TENS[tens] 
    else: 
     result = NUMBERS[n] 

    print (result) 

def convert2(): 
    if n >=100: 
     tens2 = n//100 
     units2 = n%100 

     if units2 != 0: 
      result2 = HUNNITS[tens2] + "-" + TENS[tens2] + "and" + NUMBERS[units2] 
     else: 
      result2 = HUNNITS[tens2] 
    else: 
     result2 = HUNNITS[n] 

    print(result2) 

def main(): 
    if n >=20 and n< 100: 
     x = convert() 
    if n >=100: 
     y = convert2() 

main() 

Answer 1

我不想让你灰心，但是这个问题已经解决了。有一个整洁的Python模块要做到这一点，叫num2words

这里是link to the GitHub repository

而且here is the actual script为英语（它支持多国语言）。如果仍然需要，您可以获得一些灵感来修复脚本。

Answer 2

我写了这个项目euler使用列表最初和使用python 2。有可能是错误我没有测试过太多，但它应该有希望帮助你走好

nums = ["", "one", "two", "three", "four", "five", 
    "six", "seven", "eight", "nine "] 
teens = ["", "eleven", "twelve", "thirteen", "fourteen", 
    "fifteen", "sixteen", "seventeen", "eighteen", "nineteen"] 
tens = ["", "ten", "twenty", "thirty", "forty", 
    "fifty", "sixty", "seventy", "eighty", "ninety"] 
thousands = ["","thousand", "million", "billion", "trillion"] 
def num_to_words(): 
    n= int(input("Enter number to convert: ")) 
    words = "" 
    if n == 0: 
     words += "zero" 
    else: 
     numStr = "%d" % n 
     groups = (len(numStr) + 2) // 3 
     numStr = numStr.zfill(groups * 3) 
     for i in range(0, groups*3, 3): 
      h = int(numStr[i]) 
      t = int(numStr[i+1]) 
      u = int(numStr[i+2]) 
      g = groups - (i // 3 + 1) 
      if h >= 1: 
       words += nums[h] 
       words += " hundred " 
       words+=" " 
       if int(numStr) % 100: # if number modulo 100 has remainder add "and" i.e one hundred and ten 
        words+=" and " 
      if t > 1: 
       words+= tens[t] 
       if u >= 1: 
        words+= nums[u] 
        words+=" " 
      elif t == 1: 
       if u >= 1: 
        words+= teens[(u)] 
       else: 
        words+= tens[t] 
        words+=" " 
      else: 
       if u >= 1: 
        words+= nums[u] 
        words+=" " 

      if g >= 1 and (h + t + u) > 0: 
       words+= thousands[g] 
       words+=" " 
    return words 
In [7]: num_to_words() 
Enter number to convert: 12399990 
Out[7]: 'twelvemillion three hundred and ninetynine thousand nine hundred and ninety' 

Answer 3

这可以很容易地完成递归：

def as_words(n): 
    """Convert an integer n (+ve or -ve) to English words.""" 
    # lookups 
    ones = ['zero', 'one', 'two', 'three', 'four', 
      'five', 'six', 'seven', 'eight', 'nine', 
      'ten', 'eleven', 'twelve', 'thirteen', 'fourteen', 
      'fifteen', 'sixteen', 'seventeen', 'eighteen', 'nineteen'] 
    tens = ['zero', 'ten', 'twenty', 'thirty', 'forty', 
      'fifty', 'sixty', 'seventy', 'eighty', 'ninety'] 
    # negative case 
    if n < 0: 
     return "minus {0}".format(as_words(abs(n))) 
    # 1000+ 
    for order, word in [(10**12, "trillion"), (10**9, "billion"), 
         (10**6, "million"), (10**3, "thousand")]: 
     if n >= order: 
      return "{0} {1}{2}".format(as_words(n // order), word, 
             " {0}".format(as_words(n % order)) 
             if n % order else "") 
    # 100-999 
    if n >= 100: 
     if n % 100: 
      return "{0} hundred and {1}".format(as_words(n // 100), 
               as_words(n % 100)) 
     else: 
      return "{0} hundred".format(as_words(n // 100)) 
    # 0-99 
    if n < 20: 
     return ones[n] 
    else: 
     return "{0}{1}".format(tens[n // 10], 
           "-{0}".format(as_words(n % 10)) 
           if n % 10 else "") 

Answer 4

这在Python 3.x的工作对我来说：

print('Type any number here: ') 
number = input() 
int_side = number 
dec_side = '' 
for i in range(0, len(number)): 
    if number[i] == '.': 
     int_side = number[:i] 
     dec_side = number[i + 1:] 
     break 
while not (int_side.isdigit()) or not (dec_side.isdigit()) and dec_side != '': 
    dec_side = '' 
    print('Only numbers are allowed! (decimals included, but not fractions)') 
    print('Type any number here: ') 
    number = input() 
    int_side = number 
    for i in range(0, len(number)): 
     if number[i] == '.': 
      int_side = number[:i] 
      dec_side = number[i + 1:] 
    user_choice = input() 
int_length = len(int_side) 
ones = ['', 'one ', 'two ', 'three ', 'four ', 'five ', 'six ', 'seven ', 'eight ', 'nine '] 
teens = ['ten ', 'eleven ', 'twelve ', 'thirteen ', 'fourteen ', 'fifteen ', 'sixteen ', 'seventeen ', 'eighteen ', 
     'nineteen '] 
decades = ['', '', 'twenty ', 'thirty ', 'forty ', 'fifty ', 'sixty ', 'seventy ', 'eighty ', 'ninety '] 
hundreds = ['', 'one hundred ', 'two hundred ', 'three hundred ', 'four hundred ', 'five hundred ', 'six hundred ', 
      'seven hundred ', 'eight hundred ', 'nine hundred '] 
comma = ['thousand, ', 'million, ', 'trillion, ', 'quadrillion, '] 
word = '' 
int_length = len(int_side) 
dec_length = len(dec_side) 
change = int_length 
up_change = 0 
while change > 0: 
    if int_side == '': 
     break 
    if number == '0': 
     word = 'zero' 
     break 
    elif change > 1 and int_side[change - 2] == '1': 
     for i in range(0, 10): 
      if int_side[change - 1] == str(i): 
       word = teens[i] + word 
    else: 
     if change > 0: 
      for i in range(0, 10): 
       if int_side[change - 1] == str(i): 
        word = ones[i] + word 
     if change > 1: 
      for i in range(0, 10): 
       if int_side[change - 2] == str(i): 
        word = decades[i] + word 
    if change > 2: 
     for i in range(0, 10): 
      if int_side[change - 3] == str(i): 
       word = hundreds[i] + word 
    if change > 3: 
     word = comma[up_change] + word 
    change -= 3 
    up_change += 1 
word += 'point ' 
for i in range(0, len(dec_side)): 
    for x in range(0, 10): 
     if dec_side[i] == str(x): 
      word += ones[x] 
print(word) 

这是一个例子：

Type any number here: 13243214.1324hk 
Only numbers are allowed! (decimals included, but not fractions) 
Type any number here: 13243214.1324 
thirteen million, two hundred forty three thousand, two hundred 
fourteen point one three two four