2014-08-30 39 views
0

我知道这些类型的问题之前已经被问过,但我还没有看到过这种类型。我正在使用android画布创建一个自定义的Android UI。我已经创建了所有必要的可绘它,并把它们放在相应的文件夹,现在我使用此代码绘制UI:自定义的Android用户界面和多屏幕支持

public class MainMenuView extends View { 

private Bitmap pasteImage; 
private Bitmap adventureLetters; 
private Bitmap settingsLetters; 
private Bitmap quitLetters; 
private Bitmap backgroundImage; 
private DisplayMetrics metrics; 

public MainMenuView(Context context){ 
    super(context); 
    pasteImage = decodeFile(R.drawable.paste, 200, true); 
    Log.w("Visina imagea", String.valueOf(pasteImage.getHeight())); 
    pasteImage.recycle(); 
} 

public MainMenuView(Context context, AttributeSet attrSet){ 
    super(context, attrSet); 
    metrics = context.getResources().getDisplayMetrics(); 
    pasteImage = decodeFile(R.drawable.paste, 330, true); 
    adventureLetters = decodeFile(R.drawable.adventureletters, 100, true); 
    settingsLetters = decodeFile(R.drawable.settingsletters, 100, true); 
    quitLetters = decodeFile(R.drawable.quitletters, 50, true); 
    Log.w("Je li image null? ", pasteImage == null ? "da" : "ne"); 
    backgroundImage = decodeFileScaled(R.drawable.toothpastebackground); 
    backgroundImage = Bitmap.createScaledBitmap(backgroundImage, metrics.widthPixels - 20, metrics.heightPixels, true); 
    //adventureLetters = BitmapFactory.decodeResource(getResources(), R.drawable.adventureletters); 
    //settingsLetters = BitmapFactory.decodeResource(getResources(), R.drawable.settingsletters); 
    //quitLetters = BitmapFactory.decodeResource(getResources(), R.drawable.quitletters); 
} 

@Override 
protected void onMeasure(int widthMeasure, int heightMeasure){ 
    setMeasuredDimension(calculateMeasure(widthMeasure), calculateMeasure(heightMeasure)); 
    Log.w(String.valueOf(calculateMeasure(widthMeasure)), "Izmjereno"); 
} 

private static final int DEFAULT_SIZE = 70; 
private int calculateMeasure(int measure) { 

    int result = (int)(DEFAULT_SIZE * getResources().getDisplayMetrics().density); 
    int specMode = MeasureSpec.getMode(measure); 
    int specSize = MeasureSpec.getSize(measure); 

    if(specMode == MeasureSpec.EXACTLY) result = specSize; 
    else if(specMode == MeasureSpec.AT_MOST){ 
     result = Math.min(result, specSize); 
    } 

    return result; 
} 

@Override 
protected void onDraw(Canvas canvas){ 
    super.onDraw(canvas); 
    if(canvas == null) Log.w("Canvas je null", "Da"); 
    else Log.w("Canvas nije null", "ne"); 
    Log.w("Usao u onDraw", "u onDraw sam sad"); 
    canvas.save(); 
    if(pasteImage == null) Log.w("Slika je null", "null slika"); 
    canvas.drawBitmap(backgroundImage, 0, 0, null); 
    Log.w("Dimenzije slike sirina x visina bg", backgroundImage.getWidth() + " " + backgroundImage.getHeight()); 
    canvas.drawBitmap(pasteImage, 110, 420, null); 
    canvas.drawBitmap(adventureLetters, 50, 60, null); 
    canvas.drawBitmap(settingsLetters, 80, 60, null); 
    canvas.drawBitmap(quitLetters, 100, 60, null); 
    pasteImage.recycle(); 
    adventureLetters.recycle(); 
    settingsLetters.recycle(); 
    quitLetters.recycle(); 
    canvas.restore(); 
} 

private Bitmap decodeFile(int id, int size, boolean resize){ 

     //Decode image size 
     BitmapFactory.Options o = new BitmapFactory.Options(); 
     o.inJustDecodeBounds = true; 
     BitmapFactory.decodeResource(getResources(), id, o); 

     //The new size we want to scale to 
     final int REQUIRED_SIZE = size; 

     //Find the correct scale value. It should be the power of 2. 
     int scale = 1; 
     while(o.outWidth/scale/2 >= REQUIRED_SIZE && o.outHeight/scale/2 >= REQUIRED_SIZE) 
      scale*=2; 

     //Decode with inSampleSize 
     BitmapFactory.Options o2 = new BitmapFactory.Options(); 
     o2.inSampleSize = scale; 
     return BitmapFactory.decodeResource(getResources(), id, o2); 

} 

private Bitmap decodeFileScaled(int id){ 

    final BitmapFactory.Options options = new BitmapFactory.Options(); 
    options.inJustDecodeBounds = true; 
    BitmapFactory.decodeResource(getResources(), id, options); 
    Log.w("Sirina x visina displaya", metrics.widthPixels + "x" + metrics.heightPixels); 
    options.inSampleSize = calculateScale(options, metrics.widthPixels, metrics.heightPixels); 

    options.inJustDecodeBounds = false; 
    return BitmapFactory.decodeResource(getResources(), id, options); 
} 

private int calculateScale(BitmapFactory.Options options, int reqWidth, int reqHeight){ 

    final int rawHeight = options.outHeight; 
    final int rawWidth = options.outWidth; 
    int inSampleSize = 1; 

    if (rawHeight > reqHeight || rawWidth > reqWidth) { 

     // Calculate ratios of height and width to requested height and width 
     final int heightRatio = Math.round((float) rawHeight/(float) reqHeight); 
     final int widthRatio = Math.round((float) rawWidth/(float) reqWidth); 

     // Choose the smallest ratio as inSampleSize value, this will guarantee 
     // a final image with both dimensions larger than or equal to the 
     // requested height and width. 
     inSampleSize = heightRatio < widthRatio ? heightRatio : widthRatio; 
    } 

    return inSampleSize; 
} 
} 

您可以立即,我使用一些硬编码值看到屏幕上的定位。你能给我一些关于如何编码的建议,以便它在每个屏幕上显示(特别是中,高尺寸)。因为它应该意味着不会模糊撕裂空白空间等等。如果您需要更多信息,请在评论中告诉我,非常感谢!

回答

0

您应该始终使用相对于屏幕的位置。例如:

float left = getScreenSize().x * 0.10f; 
float top = getScreenSize().y * 0.10f; 

canvas.drawBitmap(pasteImage, left, top, null); 

private float getScreenSize() { 
    WindowManager windowManager = (WindowManager) getContext.getSystemService(Context.WINDOW_SERVICE); 
    Display display = windowManager.getDefaultDisplay(); 
    Display display = getWindowManager().getDefaultDisplay(); 
    Point size = new Point(); 
    display.getSize(size); 
    return size; 
} 

,但如果你要使用的绝对值,你应该这样做在DP,没有像素。

Resources resources = getResources(); 

float left = TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, 140, resources.getDisplayMetrics()); 

float top = TypedValue.applyDimension(TypedValue.COMPLEX_UNIT_DIP, 140, resources.getDisplayMetrics()); 

canvas.drawBitmap(pasteImage, left, top, null); 
+0

有没有什么办法可以避免创建这些幻数(宽度*)等等? – Matsura 2014-08-30 13:37:17

+0

魔法? :)如果您使用视图而不是将'Drawable'绘制为'Bitmap',则可以使用'LayoutParams'来设置相对于它们自己的视图位置。 [Here](http://stackoverflow.com/questions/4638832/how-to-programmatically-set-the-layout-align-parent-right-attribute-of-a-button) – 2014-08-30 13:46:13

+0

http://stackoverflow.com/questions/25507968/android-user-interface-using-photoshop-design这就是我想要创建的。是否可以使用布局参数? – Matsura 2014-08-30 13:54:20