基于字符串中的第一个字符和最后一个字符的Python排序

Question

我在Python 2上通过谷歌在线初学者课程，我无法弄清楚其中一个问题的答案。在这里，并提前感谢您的帮助！

# A. match_ends 
# Given a list of strings, return the count of the number of 
# strings where the string length is 2 or more and the first 
# and last chars of the string are the same. 
# Note: python does not have a ++ operator, but += works. 

def match_ends(words): 
    a = [] 
    for b in words: 

return 

我尝试了几个不同的东西。这就是我最后一次尝试的时候，并决定寻求帮助。我花了更多的时间思考这个问题比我还在提

Answer 1

def match_ends(words): 
    a = [] 
    for b in words: 
     if (len(b) > 2 and b[0] == b[len(b)-1]): 
      a.append(b) 
    return a 


def match_ends2(words): 
    return [x for x in words if len(x) > 2 and x[0] == x[len(x)-1]] 

print(match_ends(['peter','paul','mary','tibet'])) 
print(match_ends2(['peter','paul','mary','tibet']))