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比方说,我已经有了喜欢的一些记录,我想在那里TYPE =“本田”和门=“4”所有剩余的记录也如何获取剩余记录的特定记录?
<Car id="1", type="honda", doors="4" created_at: "2015.01.01">
<Car id="2", type="jeep", created_at: "2015.01.01">
<Car id="3", type="mazda", created_at: "2015.01.01">
<Car id="4", type="honda", doors="4" created_at: "2015.01.01">
<Car id="5", type="honda", doors="2" created_at: "2015.01.01">
<Car id="6", type="honda", doors="2" created_at: "2015.01.01">
我想这一切汽车:
<Car id="1", type="honda", doors="4" created_at: "2015.01.01">
<Car id="2", type="jeep", created_at: "2015.01.01">
<Car id="3", type="mazda", created_at: "2015.01.01">
<Car id="4", type="honda", doors="4" created_at: "2015.01.01">
我有这个疑问,但它仅返回汽车,其中TYPE =“本田”和门=“4”主要是我不想列出其他类型的IS NOT
因为我不知道他们的价值。
Car.where("type = ? AND doors = ?", "honda", "4")
感谢您的答复,但什么是<>? – user2931706
<>是“不等于”运算符。 如果是 –
肯定,谢谢:)你可以upvote并将这个答案标记为解答。:) – user2931706