我对SQL很陌生,我试图将数据上传到我的表中。为此,我有特殊的表格,我从CSV文件上传数据,然后从这张表格中,我试图将数据复制到最终表格。外键约束失败,并在MySQL中插入选择
但现在我有一个中间表的问题,我已经上传了我的数据。该表是:
CREATE TABLE `_work_has_person` (
`work_id` int(11) NOT NULL,
`person_id` int(11) NOT NULL,
`primary_contribution_id` int(11) DEFAULT NULL,
PRIMARY KEY (`work_id`,`person_id`)
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
我希望将数据复制
CREATE TABLE `work_has_person` (
`work_id` int(11) NOT NULL,
`person_id` int(11) NOT NULL,
`primary_contribution_id` int(11) NOT NULL,
PRIMARY KEY (`work_id`,`person_id`),
KEY `fk_work_has_person_person1_idx` (`person_id`),
KEY `fk_work_has_person_work1_idx` (`work_id`),
KEY `fk_work_has_person_primary_contribution1_idx` (`primary_contribution_id`),
CONSTRAINT `fk_work_has_person_person1` FOREIGN KEY (`person_id`) REFERENCES `person` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION,
CONSTRAINT `fk_work_has_person_primary_contribution1` FOREIGN KEY (`primary_contribution_id`) REFERENCES `primary_contribution` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION,
CONSTRAINT `fk_work_has_person_work1` FOREIGN KEY (`work_id`) REFERENCES `work` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
哪家之间的中间表:
CREATE TABLE `work` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`title_work` varchar(250) DEFAULT NULL,
`subtitle_work` varchar(250) DEFAULT NULL,
`date_work` varchar(45) DEFAULT NULL,
`unix_date_work` varchar(100) DEFAULT NULL,
`sinopsis` text,
`ref_bne` varchar(100) DEFAULT NULL,
`ref_alt` longtext,
`language_id` int(11) NOT NULL,
PRIMARY KEY (`id`),
KEY `fk_work_language1_idx` (`language_id`),
KEY `title_work` (`title_work`),
CONSTRAINT `fk_work_language1` FOREIGN KEY (`language_id`) REFERENCES `language` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION
) ENGINE=InnoDB AUTO_INCREMENT=24610 DEFAULT CHARSET=utf8;
和
CREATE TABLE `person` (
`id` int(11) NOT NULL AUTO_INCREMENT,
`name` varchar(100) NOT NULL,
`img_person` varchar(250) DEFAULT NULL,
`born_date` varchar(45) DEFAULT NULL,
`unix_born_date` varchar(100) DEFAULT NULL,
`city_born_date` varchar(100) DEFAULT NULL,
`country_born_date` varchar(100) DEFAULT NULL,
`death_date` varchar(45) DEFAULT NULL,
`unix_death_date` varchar(100) DEFAULT NULL,
`city_death_date` varchar(100) DEFAULT NULL,
`country_death_date` varchar(45) DEFAULT NULL,
`biography` longtext,
`ref_bne` varchar(100) DEFAULT NULL,
`ref_alt` longtext,
PRIMARY KEY (`id`),
UNIQUE KEY `name_UNIQUE` (`name`),
KEY `name` (`name`)
) ENGINE=InnoDB AUTO_INCREMENT=9159 DEFAULT CHARSET=utf8;
但每次我尝试运行
INSERT INTO work_has_person (work_id, person_id, primary_contribution_id)
SELECT work_id, person_id, primary_contribution_id
FROM _work_has_person;
它说
Cannot add or update a child row: a foreign key constraint fails (`cdu93hfg93r`.
`work_has_person`, CONSTRAINT `fk_work_has_person_person1` FOREIGN KEY (`person_id`)
REFERENCES `person` (`id`) ON DELETE NO ACTION ON UPDATE NO ACTION)
我敢肯定的是,表中有neccesary数据,但是,¿有没有办法知道哪些数据失败?我见过Mysql error 1452 - Cannot add or update a child row: a foreign key constraint fails:但不明白如何在这里使用它。
A.
使用的东西,像'选择为person_id work_has_person减去从人身上选择id来找出无法识别的人。 –