2
我不知道这是形成这个linq查询的最佳方式,但我刚刚开始,所以任何建议表示赞赏。Linq对实体框架4.1代码首先产生左外部连接
以下查询我认为“报告中有任何项目的项目具有任何属性,其中大小属性的waiste大小属性为32.”返回报告的位置密钥,ID和名称。 (位置是从报表外键。)
var rpts = from x in ctx.Reports
where x.ReportItems.Any(y =>
y.ItemAttributes.Any(z =>
z.Sizing.WaistSize == 32))
select new { x.Key, x.Location.ID, x.Location.Name };
这将产生预期的效果,但SQL看起来不正确我。注意LEFT OUTER JOIN来获取地点名称,当它可能只是从第一内得到它加入到同一个表...
SELECT [Extent1].[ReportKey] AS [ReportKey],
[Extent2].[LocationID] AS [LocationID],
[Extent3].[LocationName] AS [LocationName]
FROM [Info].[Report] AS [Extent1]
INNER JOIN [Info].[Location] AS [Extent2]
ON [Extent1].[LocationKey] = [Extent2].[LocationKey]
LEFT OUTER JOIN [Info].[Location] AS [Extent3]
ON [Extent1].[LocationKey] = [Extent3].[LocationKey]
WHERE EXISTS
(SELECT 1 AS [C1]
FROM (SELECT [Extent4].[ReportItemKey] AS [ReportItemKey]
FROM [Info].[ReportItems] AS [Extent4]
WHERE [Extent1].[ReportKey] = [Extent4].[ReportKey]
) AS [Project1]
WHERE EXISTS (SELECT 1 AS [C1]
FROM [Info].[ItemAttributes] AS [Extent5]
INNER JOIN [Info].[Attributes] AS [Extent6]
ON [Extent5].[AttributeKey] = [Extent6].[AttributeKey]
WHERE ([Project1].[ReportItemKey] = [Extent5].[ReportItemKey])
AND ([Extent6].[WaistSize] = @p__linq__0)
)
)
感谢您的时间。