如何在onClick函数中传递JavaScript变量

Question

这里是我的代码，我想要获取点击函数中的元素信息，就像我的注释所说的那样。

for(var i = 0, len = json.length; i < length; i++) { 
    var curid = json['success'][i]['courier_id']; 
    var curname = json['success'][i]['courier_name']; 
    document.getElementById("gsid").value=curname;      
    var tr="<tr>&nbsp;&nbsp;"; 

    //here is where i want to use onclick function with curid and curname 
    var td1="<td>"+"<input type='radio' name='as' value='json['success'][i]['courier_id']' id='curiid' onclick='courierselect(<?php echo $shyam='\'+curname+\''; ?>);'/>"+"</td>&nbsp;&nbsp;"; 
    var td2="<td id='curnname'>"+json['success'][i]['courier_name']+"</td>&nbsp;&nbsp;"; 
    var td3="<td>"+json['success'][i]['country_charge']+"</td>&nbsp;&nbsp;"; 
    var td4="<td>"+json['success'][i]['estimate_delivery_time']+"</td>&nbsp;&nbsp;"; 
    var td5="<td>"+json['success'][i]['tracking_available']+"</td></tr>&nbsp;&nbsp;"; 
    $("#results").append(tr+td1+td2+td3+td4+td5); 
} 

Answer 1

我看到你的代码三个问题

• ... value='json['success'][i]['courier_id']' ...

你没有用字符串

• ... courierselect(<?php echo $shyam='\'+curname+\''; ?>) ...

  交流联系的变量
  1. echo $shyam='\'+curname+\'';您无法使用JS值设置PHP变量。 Understand why
  2. 您echo一个字符串值，所以你必须要加一些引号curname

---

for(var i = 0, len = json.length; i < length; i++) { 
    var curid = json['success'][i]['courier_id']; 
    var curname = json['success'][i]['courier_name']; 
    document.getElementById("gsid").value = curname; 

    $("#results").append('<tr>&nbsp;&nbsp;'); 
    $("#results").append('<td><input type="radio" name="as" value="' + curid + '" id="curiid" onclick="courierselect(\'' + curname + '\');"/></td>&nbsp;&nbsp;'); 
    $("#results").append('<td id="curnname">' + curname + '</td>&nbsp;&nbsp;'); 
    $("#results").append('<td>' + json['success'][i]['country_charge'] + '</td>&nbsp;&nbsp;'); 
    $("#results").append('<td>' + json['success'][i]['estimate_delivery_time'] + '</td>&nbsp;&nbsp;'); 
    $("#results").append('<td>' + json['success'][i]['tracking_available'] + '</td></tr>&nbsp;&nbsp;'); 
}