我有这样的PHP代码:错误:mysql_fetch_array预计资源,布尔给
$con = mysqli_connect("localhost","root","","dbjobsheetsf");
$sql1 = "SELECT colDate FROM tbljs ";
$queryR = mysql_query($sql1);
$p = 0;
echo "<select name=\"jsGetDate\">";
while($r = mysql_fetch_array($queryR)) {
echo "<option value=".$r["colDate"].">".$r["colDate"]."</option>";
}
echo "</select>";
mysqli_close($con);
,我发现了错误:
mysql_fetch_array() expects parameter 1 to be resource, boolean given
反正是有解决这个问题?
问题解决 谢谢先生约翰罗伯逊你是一个很大的帮助!
+1用于捕获'mysqli_query'连接参数,我甚至没有看到! – meda 2014-08-28 03:27:17