我使用system.Net.Socket从服务器发送和接收消息时client.but多个服务器广播消息,然后接收器程序被突然关闭现在面临的问题。当有多个服务器广播时,客户端如何接收多个广播消息?
广播我的服务器的代码如下..
using System;
using System.Net;
using System.Net.Sockets;
using System.Text;
public class Broadcst
{
public static void Main()
{
Socket sock = new Socket(AddressFamily.InterNetwork, SocketType.Dgram, ProtocolType.Udp);
IPEndPoint iep1 = new IPEndPoint(IPAddress.Broadcast, 9050);
IPEndPoint iep2 = new IPEndPoint(IPAddress.Parse("192.168.1.255"), 9050);
string hostname = Dns.GetHostName();
byte[] data = Encoding.ASCII.GetBytes(hostname);
sock.SetSocketOption(SocketOptionLevel.Socket, SocketOptionName.Broadcast, 1);
sock.SendTo(data, iep1);
sock.SendTo(data, iep2);
sock.Close();
}
}
我的收款人代码是客户端如下...
using System;
using System.Net;
using System.Net.Sockets;
using System.Text;
public class RecvBroadcst
{
public static void Main()
{
Socket sock = new Socket(AddressFamily.InterNetwork,
SocketType.Dgram, ProtocolType.Udp);
While(true){
IPEndPoint iep = new IPEndPoint(IPAddress.Any, 9050);
sock.Bind(iep);
EndPoint ep = (EndPoint)iep;
Console.WriteLine("Ready to receive...");
byte[] data = new byte[1024];
int recv = sock.ReceiveFrom(data, ref ep);
string stringData = Encoding.ASCII.GetString(data, 0, recv);
Console.WriteLine("received: {0} from: {1}",
stringData, ep.ToString());
data = new byte[1024];
recv = sock.ReceiveFrom(data, ref ep);
stringData = Encoding.ASCII.GetString(data, 0, recv);
Console.WriteLine("received: {0} from: {1}",
stringData, ep.ToString());
}
sock.Close();
}
}
因此,如何能在客户端接收一个以上的广播有多个服务器广播时的消息?
当我从服务器再次发送消息等其投掷的错误“的每个套接字地址(协议/网络地址/端口)只有一个的使用通常被许可”
你的接收器程序只要它已经收到一个消息,“突然退出”,因为这是你写的方式。如果您希望它收到多条消息,请相应地调整代码。这里有什么问题? – EJP
我已经把这些代码中,而真正但是从服务器发送一条消息时,其接近与应该有任何message.see我更新的问题 –
该计划不仅是在“关闭”。它由于未处理的异常而失败。解释该例外情况非常重要。 – usr