2013-11-21 18 views

回答

0

试试这个:

function getURLParameter(name, urlsearch) { 

     return decodeURIComponent((new RegExp('[?|&]' + name + '=' + '([^&;]+?)(&|#|;|$)').exec(urlsearch || location.search) || [ , "" ])[1].replace(
       /\+/g, '%20')) 
       || null; 
    } 

    var url = "Posts?Category=1134324"; 

    alert(getURLParameter('Category', url)); 

http://jsfiddle.net/kL9DJ/