Mysql的集团通过功能

这是我的表：Mysql的集团通过功能

Id customer email  timestamp    store_id 
1 1  [email protected] 2014-04-11 17:06:21 5416 
2 0  [email protected] 2014-04-11 15:05:23 5416 
3 1  [email protected] 2014-04-11 17:55:34 5416 
4 2  [email protected] 2014-04-11 17:55:34 5416

和我的查询是：

SELECT *, count(*) as total FROM `tybo_orders` 
WHERE timestamp IN (SELECT max(timestamp) FROM `tybo_orders` 
GROUP BY email) AND store_id='5416' GROUP BY email

0在customer列中的值表示访客和超过0意味着客户ID。如果customer为0，则我想通过email进行分组，其他分组由customer进行分组。这怎么可能？

来源

2014-04-12 Prakash

使用case语句适用condtions – Divya

什么是你想要的输出？ – wils484

尝试像这样

SELECT *, count(*) as total 
FROM `tybo_orders` 
WHERE timestamp IN (SELECT max(timestamp) FROM `tybo_orders` GROUP BY email) 
AND 
store_id='5416' 
GROUP BY 
case when customer=0 then customer else email end

来源

2014-04-12 05:19:13 Sathish

，我认为这会工作：

SELECT *, count(*) as total 
FROM `tybo_orders` 
WHERE timestamp IN (SELECT max(timestamp) FROM `tybo_orders` GROUP BY email) 
AND 
store_id='5416' 
GROUP BY 
IF(customer=0,email,customer)

来源

2014-04-12 05:00:16

Mysql的集团通过功能

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