如何从Angular的JSON数据中提取特定的键？

-5

我有以下的JSON，我想提取唯一的位置，并把它放在另一个JSON或数组中与以前相同的格式。我是一个新手，因此，对我来说有点困惑。如何从Angular的JSON数据中提取特定的键？

这是我有：

let data = { 
    "Person" : [{"name":"harman","comment_count":255}, 
       {"name":"aman","comment_count":66}, 
       {"name":"mukesh","comment_count":66}], 
    "location": [{"name":"delhi","comment_count":255}, 
       {"name":"mumbai","comment_count":66}, 
       {"name":"chandigarh","comment_count":66}], 
    "org  ": [{"name":"dell","comment_count":255}, 
       {"name":"apple","comment_count":66}, 
       {"name":"hp","comment_count":66}], 
    "teams" : [{"name":"Real","comment_count":255}, 
       {"name":"Juve","comment_count":66}, 
       {"name":"Liverpool","comment_count":66}]   
};

这就是我想要的：

data2 = { 
    "location": [ 
     {"name":"delhi","comment_count":255}, 
     {"name":"mumbai","comment_count":66}, 
     {"name":"chandigarh","comment_count":66}]  
};

来源

2017-02-23 Harman

非常基本的东西 –

'data2.location = data.location;' –

做到这一点。

data2 = data.location

来源

2017-02-23 08:45:24 dgoku

包括下面的代码片段。只需使用var data2 = data.location;好运


 
    window.onload = function(){ 
 
    
 
     let data = { 
 
         "Person" : [{"name":"harman","comment_count":255}, 
 
            {"name":"aman","comment_count":66}, 
 
            {"name":"mukesh","comment_count":66}], 
 
         "location": [{"name":"delhi","comment_count":255}, 
 
            {"name":"mumbai","comment_count":66}, 
 
            {"name":"chandigarh","comment_count":66}], 
 
         "org  ": [{"name":"dell","comment_count":255}, 
 
            {"name":"apple","comment_count":66}, 
 
            {"name":"hp","comment_count":66}], 
 
         "teams" : [{"name":"Real","comment_count":255}, 
 
            {"name":"Juve","comment_count":66}, 
 
            {"name":"Liverpool","comment_count":66}]   
 
     }; 
 
     
 
     var data2 = data.location; 
 
     console.log("data2:"); 
 
     console.log(data2); 
 
    
 
    };

来源

2017-02-23 08:46:43 BFG

如何从Angular的JSON数据中提取特定的键？

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