数据存储在Android的

Question

从链接XML我从该链接的链接：从这个链接

http://api.maxxiscentral.com/maxxiscentral/GetTyrePatterns

我想赶数据串，并从该字符串我想创建的XML文件。

package com.androidpeople.xml.parsing; 

import java.net.URL; 
import javax.xml.parsers.SAXParser; 
import javax.xml.parsers.SAXParserFactory; 
import org.xml.sax.InputSource; 
import org.xml.sax.XMLReader; 
import android.app.Activity; 
import android.os.Bundle; 
import android.widget.LinearLayout; 
import android.widget.TextView; 

public class XMLParsingExample extends Activity { 

    /** Create Object For SiteList Class */ 
    SitesList sitesList = null; 

    /** Called when the activity is first created. */ 
    @Override 
    public void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.main); 

     /** Create a new layout to display the view */ 
     LinearLayout layout = new LinearLayout(this); 
     layout.setOrientation(1); 

     /** Create a new textview array to display the results */ 
     TextView name[]; 
     TextView website[]; 
     TextView category[]; 

     try { 

      /** Handling XML */ 
      SAXParserFactory spf = SAXParserFactory.newInstance(); 
      SAXParser sp = spf.newSAXParser(); 
      XMLReader xr = sp.getXMLReader(); 

      /** Send URL to parse XML Tags */ 
      URL sourceUrl = new URL(
        "http://api.maxxiscentral.com/maxxiscentral/GetTyrePatterns"); 

      /** Create handler to handle XML Tags (extends DefaultHandler) */ 
      MyXMLHandler myXMLHandler = new MyXMLHandler(); 
      xr.setContentHandler(myXMLHandler); 
      xr.parse(new InputSource(sourceUrl.openStream())); 

     } catch (Exception e) { 
      System.out.println("XML Pasing Excpetion = " + e); 
     } 

     /** Get result from MyXMLHandler SitlesList Object */ 
     sitesList = MyXMLHandler.sitesList; 

     /** Assign textview array lenght by arraylist size */ 
     name = new TextView[sitesList.getName().size()]; 
     website = new TextView[sitesList.getName().size()]; 
     category = new TextView[sitesList.getName().size()]; 

     /** Set the result text in textview and add it to layout */ 
     for (int i = 0; i < sitesList.getName().size(); i++) { 
      name[i] = new TextView(this); 
      name[i].setText("Name = "+sitesList.getName().get(i)); 
      website[i] = new TextView(this); 
      website[i].setText("Website = "+sitesList.getWebsite().get(i)); 
      category[i] = new TextView(this); 
      category[i].setText("Website Category = "+sitesList.getCategory().get(i)); 

      layout.addView(name[i]); 
      layout.addView(website[i]); 
      layout.addView(category[i]); 
     } 


     /** Set the layout view to display */ 
     setContentView(layout); 

    } 
} 

我有这样的代码字符串转换成XML，但是，在Java

这个代码运行而不是在android系统。为什么？

以及如何从该链接获取数据。

感谢先进。

Answer 1

get from here get it
get it
get it
get it