如何删除foreach（）中的“，”？

Question

我有一个代码PHP

foreach ($cities as $city) { 
    echo substr($city->name . ", ", 0, -2); 
} 

结果是：A，B，C，d，E，

如何用的foreach除去 “”（）

正确：a，b，c，d，e

Answer 1

$first = true; 
foreach ($cities as $city) { 
    if(!$first){ 
     echo ', '; 
    }else{ 
     $first = false; 
    } 
    echo $city->name; 
} 

Answer 2

更改它有点像：

$first = TRUE; 

foreach ($cities as $city) 
{ 
    if (!$first) 
    { 
     echo(","); 
    } 

    $first = FALSE; 
    echo($city->name); 
} 

Answer 3

$str = ''; 
foreach ($cities as $city){ 
    $str .= "$city, "; 
} 
$str = rtrim($str, " ,"); 

Answer 4

使用rtrim的foreach()后：

$city->name = rtrim($city->name,','); 

Answer 5

你可以实现用更少的代码相同，通过使用implode功能。

$comma_separated = implode(',', $cities); 

应该给你正是你想要的。

Answer 6

方法1：

$index = 0; 
    foreach ($cities as $city) { 
    $index++; 
    echo $city->name . ($index == count($cities)?"":","); 

    } 

方法2：

$str = ""; 
    foreach ($cities as $city) { 
    $str .= $city->name . ",";  
    } 
$str = substr_replace($str ,"",-1); 
echo $str; 

Answer 7

在这种情况下，你不能没有额外的标记去掉最后一个逗号。

您还有其他两个选项：

1.使用循环标准：

for ($i=0; $i < count($cities)-1; $i++) { 
    echo $cities[$i]->name . ", "; 
} 
echo $cities(count($cities)-1)->name; 

2.在foreach创建一个结果字符串，删除最后一个字符，比打印它。

Answer 8

只要做到： -

echo implode(',', $cites);

这会给你所需的输出。
我只是从你的代码注意到$cities是一个对象不是一个数组，抱歉： - 字符串和从字符串最后`，`最后删除

foreach($cities as $city){ 
    $cityNames[] = $city->name; 
} 
echo implode(',', $cityNames); 

http://www.php.net/implode