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我给出了函数{1,2,3,4,5}。我必须接收用户输入他想要的有多少个有序对,然后验证该函数是否有效(x坐标的值必须在1到5之间,并且x坐标不能重复)。我知道如何循环并检查X的值是否在1和5之间,但是,我无法检查字符串是否有重复元素。我写了x小于1且大于5的条件表达式,但我难以理解如何编写一个检查重复元素的表达式。有人可以帮我吗?这是我到目前为止有:检查数学函数是否有效
import java.util.Scanner;
public class Functions
{
public static void main (String args [])
{
Scanner in = new Scanner (System.in);
int []domain = new int [5];
int [] range = new int [5];
int orderedPairs = 0;
System.out.println ("Enter the number of ordered pairs please: ");
orderedPairs = in.nextInt();
while (orderedPairs < 0 || orderedPairs > 5)
{
System.out.println ("This input is invalid. Enter a number between 0 and 5 and try again:");
orderedPairs = in.nextInt();
}
for (int i = 0; i < orderedPairs; i++)
{
System.out.println ("Enter the x-coordinate please: ");
domain [i][0] = in.nextInt();
System.out.println ("Enter the y-coordinate please: ");
range [i][0] = in.nextInt();
}
for (int i = 0; i < orderedPairs; i++)
{
System.out.println ("f(" + domain [i][0] + "): " + range [i][0]);
}
for (int i = 0; i < orderedPairs;i++)
{
if (domain [i][0] > 5 || domain [i][0] < 1)
{
function = false;
}
for (int n = i + 1; n < orderedPairs; n++)
{
if (domain[i] == domain [n] && range [n] != range [i])
{
function = false;
}
}
}
}
}
编辑: 这是所有花了,显然! :)
如果这是功课,请添加“家庭作业”标签。 – 2012-01-17 23:09:56