php爆炸字符

Question

每隔三个分号（;）如何爆炸？

示例数据： $ string = piece1; piece2; piece3; piece4; piece5; piece6; piece7; piece8;

例子输出为：

$output[0] = piece1;piece2:piece3; 

$output[1] = piece4;piece5;piece6; 

$output[2] = piece7;piece8; 

谢谢！

Answer 1

我相信你可以用正则表达式来做一些漂亮的事情，但是为什么不分解每一个半色，然后一次添加三个。

$tmp = explode(";", $string); 
$i=0; 
$j=0; 

foreach($tmp as $piece) { 
    if(! ($i++ %3)) $j++; //increment every 3 
    $result[$j] .= $piece; 
} 

Answer 2

也许从不同的角度来看待它。将所有内容分解（），然后再将它合并为三部分。像这样...

$str = "1;2;3;4;5;6;7;8;9"; 
$boobies = explode(";", $array); 
while (!empty($boobies)) 
{ 
    $foo = array(); 
    $foo[] = array_shift($boobies); 
    $foo[] = array_shift($boobies); 
    $foo[] = array_shift($boobies); 
    $bar[] = implode(";", $foo) . ";"; 
} 

print_r($bar); 

阵列 （ [0] => 1; 2; 3; [1] => 4; 5; 6; [2] => 7; 8; 9 ; ）

Answer 3

$string = "piece1;piece2;piece3;piece4;piece5;piece6;piece7;piece8;piece9;"; 
preg_match_all('/([A-Za-z0-9\.]*;[A-Za-z0-9\.]*;[A-Za-z0-9\.]*;)/',$string,$matches); 

print_r($matches); 

Array 
(
    [0] => Array 
     (
      [0] => piece1;piece2;piece3; 
      [1] => piece4;piece5;piece6; 
      [2] => piece7;piece8;piece9; 
     ) 

    [1] => Array 
     (
      [0] => piece1;piece2;piece3; 
      [1] => piece4;piece5;piece6; 
      [2] => piece7;piece8;piece9; 
     ) 

) 

Answer 4

这里有一个正则表达式的方法，这我不能说是太漂亮。

$str=''; 
for ($i=1; $i<20; $i++) { 
    $str .= "$i;"; 
} 

$split = preg_split('/((?:[^;]*;){3})/', $str, -1, 
        PREG_SPLIT_NO_EMPTY | PREG_SPLIT_DELIM_CAPTURE); 

输出：

Array 
(
    [0] => 1;2;3; 
    [1] => 4;5;6; 
    [2] => 7;8;9; 
    [3] => 10;11;12; 
    [4] => 13;14;15; 
    [5] => 16;17;18; 
    [6] => 19; 
) 

Answer 5

另一个正则表达式的方法。

<?php 
$string = 'piece1;piece2;piece3;piece4;piece5;piece6;piece7;piece8'; 
preg_match_all('/([^;]+;?){1,3}/', $string, $m, PREG_SET_ORDER); 
print_r($m); 

结果：

Array 
(
    [0] => Array 
     (
      [0] => piece1;piece2;piece3; 
      [1] => piece3; 
     ) 

    [1] => Array 
     (
      [0] => piece4;piece5;piece6; 
      [1] => piece6; 
     ) 

    [2] => Array 
     (
      [0] => piece7;piece8 
      [1] => piece8 
     ) 

) 

Answer 6

正则表达式拆分

$test = ";2;3;4;5;6;7;8;9;10;;12;;14;15;16;17;18;19;20"; 
// match all groups that: 
// (?<=^|;) follow the beginning of the string or a ; 
// [^;]* have zero or more non ; characters 
// ;? maybe a semi-colon (so we catch a single group) 
// [^;]*;? again (catch second item) 
// [^;]* without the trailing ; (to not capture the final ;) 
preg_match_all("/(?<=^|;)[^;]*;?[^;]*;?[^;]*/", $test, $matches); 
var_dump($matches[0]); 


array(7) { 
    [0]=> 
    string(4) ";2;3" 
    [1]=> 
    string(5) "4;5;6" 
    [2]=> 
    string(5) "7;8;9" 
    [3]=> 
    string(6) "10;;12" 
    [4]=> 
    string(6) ";14;15" 
    [5]=> 
    string(8) "16;17;18" 
    [6]=> 
    string(5) "19;20" 
} 

Answer 7

本质上相同的解决方案与其他那些explode并再次加入...

$tmp = explode(";", $string); 

while ($tmp) { 
    $output[] = implode(';', array_splice($tmp, 0, 3)); 
}; 

Answer 8

最简单的办法我可以认为o f为：

$chunks = array_chunk(explode(';', $input), 3); 
$output = array_map(create_function('$a', 'return implode(";",$a);'), $chunks);