FOSUserBundle：根据角色设置独特角色和认证URL

Question

如何修改security.yml以实现此方案？

情景：

• mysitessss.com - >student，lecturer和manager可以访问
• mysitessss.com/admin - >lecturer和manager可以访问
• mysitessss.com/admin/private - >manager可以访问

我应该运行哪个确切的命令来创建相应的u SERS？

• 学生：php app/console fos：user：create ?????????
• 教师：php app/console fos：user：create ?????????
• 经理：php app/console fos：user：create ?????????

我读了documentation和this post但我很困惑！

的routing.yml

home: 
    path:/

admin: 
    path: /admin 

admin_private: 
    path: /admin/private 

应用程序/配置/ security.yml

security: 
    role_hierarchy: 
     ROLE_STUDENT: ????????? 
     ROLE_LECTURER: ???????????? 
     ROLE_MANAGER: ??????? 

    access_control: 
     - { path: ^/login$, role: IS_AUTHENTICATED_ANONYMOUSLY } 
     - { path: ^/register, role: IS_AUTHENTICATED_ANONYMOUSLY } 
     - { path: ^/resetting, role: IS_AUTHENTICATED_ANONYMOUSLY } 
     - { path: ^/, role: ????????? } 
     - { path: ^/admin, role: ????????? } 
     - { path: ^/admin/private, role: ?????????? } 

Answer 1

我觉得你这样的security.yml会长相：

security: 
    role_hierarchy: 
     ROLE_LECTURER: [ROLE_STUDENT] 
     ROLE_MANAGER: [ROLE_LECTURER] 

    access_control: 
     - { path: ^/login$, role: IS_AUTHENTICATED_ANONYMOUSLY } 
     - { path: ^/register, role: IS_AUTHENTICATED_ANONYMOUSLY } 
     - { path: ^/resetting, role: IS_AUTHENTICATED_ANONYMOUSLY } 
     - { path: ^/, role: ROLE_STUDENT } 
     - { path: ^/admin, role: ROLE_LECTURER } 
     - { path: ^/admin/private, role: ROLE_MANAGER } 

你可以创建 他们每个用户和促进作用：

$ php app/console fos:user:create student 
$ php app/console fos:user:promote student ROLE_STUDENT 
$ php app/console fos:user:create lecturer 
$ php app/console fos:user:promote lecturer ROLE_LECTURER 
# ... etc.