如何从Javascript中的另一个数组值中过滤数组值？

Question

我在我的演示应用程序中有两个数组。数组一个有内容的国家另一个是列表国家。所以，如果该国家不包含在国家阵列中，我想从国家阵列中移除国家。我已经把我下面的数组值，

var continent = [ 
    { 
     "continent":"Europe", 
     "country":["Albania", "Andorra", "UK", "Ireland"] 
    }, 
    { 
     "continent":"Asia", 
     "country":["Armenia", "Cambodia", "China", "Cyprus"] 
    } 
] 

var selectedCountries = ["Albania", "Andorra", "Armenia"]; 

输出

var result = [ 
    { 
     "continent":"Europe", 
     "country":["Albania", "Andorra"] 
    }, 
    { 
     "continent":"Asia", 
     "country":["Armenia"] 
    } 
] 

Answer 1

output=continent.map(continent=>{ 
    return { 
     country:continent.country.filter(country=>selectedCountries.find(c=>c===country)), 
     continent:continent.continent 
    }; 
}); 

只过滤由selectCountries阵列的国...

http://jsbin.com/lagonukuni/edit?console

Answer 2

如果你正在寻找修改orig伊纳勒数组，你可以这样做：

forEach and `filter` would do the job. 

1. 只是遍历数组continent。
2. 对于包含country数组的每个对象，请保留selectedCountries集合中的对象。

var continent = [ 
 
    { 
 
     "continent":"Europe", 
 
     "country":["Albania", "Andorra", "UK", "Ireland"] 
 
    }, 
 
    { 
 
     "continent":"Asia", 
 
     "country":["Armenia", "Cambodia", "China", "Cyprus"] 
 
    } 
 
]; 
 

 
var selectedCountries = ["Albania", "Andorra", "Armenia"]; 
 

 
continent.forEach(function (c,i) { 
 
    c.country = c.country.filter(function (v,i) { 
 
    return selectedCountries.includes(v); 
 
    }); 
 
}); 
 
console.log(continent);