字符串解析为一个特定的格式

Question

string = std::vector<int>(6,0)，并希望为{ 0 0 0 0 0 0 }

我想这

#include <iostream> 
using namespace std; 


int main() 
{ 
    string str = "std::vector<int>(6,0)" ; 

    unsigned found = str.find('('); 
    char c = str[found+1]; 
    int i = c - '0'; 
    char ch = str[found+3]; 
    int j = ch - '0'; 

    str = "{ "; 
    for(int k = 0; k < i ; k++) 
    { 
     str = str + ch + " " ; 
    } 

    str = str + " }"; 

    cout << str << endl; 

    return 0; 
} 

它的工作原理，但并没有看起来非常高效的IT显示。有什么更好的想法

Answer 1

当前版本的代码仅适用于矢量和元素大小的单个数字值。使用std::stringstream了一下更好的解决方案：

#include <iostream> 
#include <sstream> 

using namespace std; 


int main() 
{ 

    string str = "std::vector<int>(6,0)" ; 

    unsigned found = str.find('('); 
    string arguments = str.substr(found); 

    // Replace non-numeric chars with spaces. 
    for (unsigned i=0;i<arguments.size(); ++i) { 
    if (!isdigit(arguments[i])) { 
     arguments[i] = ' '; 
    } 
    } 

    std::istringstream iss(arguments); 
    int size; 
    // String to avoid having to cast later on 
    string value; 
    iss >> size >> value; 

    string res = "{; 

    for (int i = 0; i < size; ++i) { 
    res += " " + value; 
    } 
    res += " }"; 

    cout << res; 
    return 0; 
} 

Answer 2

下面是更灵活（希望）位的代码的另一个版本。它发现“（”sing，then“）”用逗号分割它们，去掉所有的空白字符并将数字转换为整数。然后它将它们打印出来。

#include <string> 
#include <iostream> 
using namespace std; 

//these three functions are taken from here: 
//http://stackoverflow.com/questions/216823/whats-the-best-way-to-trim-stdstring 

#include <algorithm> 
#include <functional> 
#include <cctype> 
#include <locale> 

static inline std::string &ltrim(std::string &s) { 
     s.erase(s.begin(), std::find_if(s.begin(), s.end(), std::not1(std::ptr_fun<int, int>(std::isspace)))); 
     return s; 
} 

// trim from end 
static inline std::string &rtrim(std::string &s) { 
     s.erase(std::find_if(s.rbegin(), s.rend(), std::not1(std::ptr_fun<int, int>(std::isspace))).base(), s.end()); 
     return s; 
} 

// trim from both ends 
static inline std::string &trim(std::string &s) { 
     return ltrim(rtrim(s)); 
} 

int main() 
{ 
    string s = "std::vector<int>(612,30)"; 

    int paren_start = s.find("(")+1; 

    string numbers = s.substr(paren_start, s.find(")")-paren_start); 
    int comma_pos = numbers.find(","); 

    string first_num = numbers.substr(0, comma_pos); 
    string second_num = numbers.substr(comma_pos+1, numbers.size()-comma_pos); 

    int first = atoi(trim(first_num).c_str()); 
    int second = atoi(trim(second_num).c_str()); 

    cout << "{" << endl; 
    for(int i=0; i<first; i++) 
    { 
     cout << second << " "; 
    } 
    cout << "}" << endl; 

    return 0; 
}