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我有一个代码,它禁用页面加载时的按钮,因为下拉列表的值为空。但是,如果选择了一个值(这些值来自数据库,它已填充且正在工作),则该按钮仍处于禁用状态。如果在下拉菜单中没有选择的值,则禁用按钮
的Jquery:
<script>
$(document).ready(function(){
$('.send').attr('disabled',true);
$('#kagawad').keyup(function(){
if($(this).val() != ""){
$('.send').attr('disabled', false);
}
else
{
$('.send').attr('disabled', true);
}
})
});
</script>
HTML:
<div class="item form-group">
<label class="control-label col-md-3 col-sm-3 col-xs-12">Select Kagawad</label>
<div class="col-md-9 col-sm-9 col-xs-12">
<?php
include 'config.php';
$selectSql = "SELECT firstName, middleName, lastName
FROM table_position p
LEFT JOIN person r ON p.Person_idPerson = r.idPerson
WHERE p.bar_position = 'Barangay Kagawad' AND p.activeOrInactive = 'Active'";
$result = mysqli_query($conn, $selectSql);
?>
<select class="form-control" id = "kagawad" name = "kagawad" required>
<option value="">Choose...</option>
<?php
while ($line = mysqli_fetch_array($result)) {
?>
<option value="<?php echo $line['firstName'].' '.$line['middleName'].' '.$line['lastName'];?>"> <?php echo $line['firstName'].' '.$line['middleName'].' '.$line['lastName'];?> </option>
<?php
mysqli_close($conn);
}
?>
</select>
</div>
<button id="send" type="submit" class="send btn btn-success" name="addCedula">Save Record</button>
我该怎么办呢?我需要修改我的代码?谢谢!
我需要的!非常感谢。你解决了我的问题。谢谢@Tushar! –