我很疑惑...我有这个函数“colorWithHexString”...当我将它包含在调用它的viewcontroller中时,它工作正常。但是当我将它移动到一个单独的“BSJax”类并使用相同的输入参数调用它时,它会引发无法识别的选择器错误。这里的电话:无法识别的选择器灾难
BSjax *bsjax = [BSjax new];
NSString *hexString = [NSString stringWithString:@"CCCCFF"];
[self.view setBackgroundColor:[bsjax colorWithHexString:hexString]];
我敢肯定有一些关于我打电话,防止它作为一个bsjax方法工作的功能的方式。任何反馈将不胜感激。
BSjax.h包括:
+ (UIColor *)colorWithHexString:(NSString *)stringToConvert;
...和BSjax.m包括:
+ (UIColor *)colorWithHexString:(NSString *)stringToConvert
{
NSString *cString = [[stringToConvert stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceAndNewlineCharacterSet]] uppercaseString];
// String should be 6 or 8 characters
if ([cString length] < 6) NSLog(@"colorWithHexString called with parameter < 6 characters in length");
// strip 0X if it appears
if ([cString hasPrefix:@"0X"]) cString = [cString substringFromIndex:2];
if ([cString length] != 6) NSLog(@"colorWithHexString called with parameter != 6 characters in length");
// Separate into r, g, b substrings
NSRange range;
range.location = 0;
range.length = 2;
NSString *rString = [cString substringWithRange:range];
range.location = 2;
NSString *gString = [cString substringWithRange:range];
range.location = 4;
NSString *bString = [cString substringWithRange:range];
// Scan values
unsigned int r, g, b;
[[NSScanner scannerWithString:rString] scanHexInt:&r];
[[NSScanner scannerWithString:gString] scanHexInt:&g];
[[NSScanner scannerWithString:bString] scanHexInt:&b];
return [UIColor colorWithRed:((float) r/255.0f)
green:((float) g/255.0f)
blue:((float) b/255.0f)
alpha:1.0f];
}
发布您的colorWithHexString的方法定义,并请张贴在它定义的位置(哪个文件) – coneybeare 2010-06-05 01:44:06
@coneybeare ... k,添加了声明和定义......令人费解的是当我将该函数移动到viewcontroller本身改变任何东西...嗯,我改变它是一个私人的方法,而不是公共...它的作品就像一个魅力) – codemonkey 2010-06-05 01:49:47
我很难理解指针和内存管理,并想知道如果我应该保留我的十六进制字符串变量或东西? – codemonkey 2010-06-05 01:50:49