JSON分离变量

我有下面的代码是通过JSON输出。JSON分离变量

stdClass Object 
(
    [event_type] => transaction.created 
    [event_resource] => stdClass Object 
     (
      [id] => tran_9x2x8xex5x7xexex0x8x9xexexbx 
      [amount] => 9980 
      [origin_amount] => 9980 
      [status] => open 
      [description] => 9xax1x7x5x8x2xaxaxcx4x5xfx8x2x2x 
      [livemode] => 1 
      [refunds] => 
      [currency] => GBP 
      [created_at] => 1375307922 
      [updated_at] => 1375307922 
      [response_code] => 10001 
      [short_id] => 
      [is_fraud] => 
      [invoices] => Array 
       (
       ) 

      [app_id] => 
      [fees] => Array 
       (
       ) 

      [payment] => stdClass Object 
       (
        [id] => pay_7xdxex9xfxcx6x3x9x5x7xcx 
        [type] => creditcard 
        [client] => client_2x2xex0x2x4xx3bx3x6x 
        [card_type] => mastercard 
        [country] => 
        [expire_month] => 10 
        [expire_year] => 2015 
        [card_holder] => XXX XXXXXX 
        [last4] => 8XX8 
        [created_at] => 1375307921 
        [updated_at] => 1375307922 
        [app_id] => 
       ) 

      [client] => stdClass Object 
       (
        [id] => client_2x2xex0x2x4xfx3x3x6x 
        [email] => 
        [description] => 
        [created_at] => 1375307922 
        [updated_at] => 1375307922 
        [app_id] => 
        [payment] => Array 
         (
         ) 

        [subscription] => 
       ) 

      [preauthorization] => 
     ) 

    [created_at] => 1375307922 
    [app_id] => 
) 


Event Rosource ID = tran_9x2x8xex5x7xexex0x8x9xexexbx

我需要能够把每个变量，并把它简单的东西，如

$ eventresourceid = tran_9x2x8xex5x7xexex0x8x9xexexbx

$ eventresourceamount = 9980

谁能告诉我怎么能去做这个？

来源

2013-08-01 user1491318

什么特别是给你一个困难时期？从JSON中读取对象？在对象被反序列化之后处理对象？到目前为止，你有没有尝试过任何代码？ – rutter

使用$obj->event_resource->id和$obj->event_resource->amount

来源

2013-08-01 21:14:50 exussum

回答

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