2014-03-26 50 views
0

我想下面的查询来获得总的余额和日期使用条形图,它的工作,但返回2条目相同的日期,如果有2个条目使用该日期,但我想组这些日期在1日......复杂的查询,以获得每天的总余额

MySQL查询...

SELECT dnt, 
@running_bal := @running_bal + (`Credit` - `Debit`) as `Balance` 
FROM transactions, (SELECT @running_bal := 0) tempName 
ORDER BY dnt ASC 

例结果...

+----------------------+-----------+ 
|   dnt   | Balance | 
+----------------------+-----------+ 
| 2014-03-06 10:30:00 | 28350.00 | 
| 2014-03-06 10:30:00 | 29295.00 | 
| 2014-03-13 09:30:00 | 57645.00 | 
| 2014-03-13 09:30:00 | 85995.00 | 
| 2014-03-17 09:30:00 | 114345.00 | 
| 2014-03-20 09:30:00 | 134190.00 | 
| 2014-03-26 20:02:30 | 133690.00 | 
+----------------------+-----------+ 

回答

1

事情是这样的:

SELECT dnt, 
    @running_bal := @running_bal + `Balance` as `Balance` 
FROM 
    (SELECT dnt, SUM(Credit) - SUM(Debit) as `Balance` FROM transactions GROUP BY dnt) tmp, 
    (SELECT @running_bal := 0) tempName 
ORDER BY dnt ASC 
+0

谢谢,但得到这个错误......'每个派生表都必须有自己的别名' – seoppc

+0

@seoppc查看更新。 –

+0

谢谢,它解决了我的问题。我会接受这个答案,并让我知道你是否可用于较小的mysql项目。 – seoppc