0
在我的编码,将遵循一种方法,我有3个clickCounts所有垂直和我想知道是否有这样的代码自动移动最高的clickCount到顶部:有自动订购一组的clickCount的
下面是代码我迄今为止:
<!DOCTYPE html>
<html>
<head>
<meta content="text/html; charset=utf-8" http-equiv="Content-Type">
<script type="text/javascript">
function countClicks() {
var x = 0;
x += 1
document.getElementById("counting").innerHTML = x;
var clickLimit = 1; //Max number of clicks
if(x>=clickLimit) {
}
else
{
ClickCount++;
return true;
}
}
</script>
<script type="text/javascript">
function countClicks1() {
var x = 0;
x += 1
document.getElementById("counting1").innerHTML = x;
var clickLimit = 1; //Max number of clicks
if(x>=clickLimit) {
}
else
{
ClickCount++;
return true;
}
}
</script>
<script type="text/javascript">
function countClicks2() {
var x = 0;
x += 1
document.getElementById("counting2").innerHTML = x;
var clickLimit = 1; //Max number of clicks
if(x>=clickLimit) {
}
else
{
ClickCount++;
return true;
}
}
</script>
</head>
<body>
<div style="margin-left:100px;">
<img src="../Pictures/BWS + L.A +KUSH/Game.RED_Album_Cover.jpg" alt="red album"><br>
<input type="button" value="VOTE" name="clickOnce" onclick="return countClicks();" />
<div id="counting"></div>
<img src="../Pictures/BWS + L.A +KUSH/Game.RED_Album_Cover.jpg" alt="red album"><br>
<input type="button" value="VOTE" name="clickOnce" onclick="return countClicks1();" />
<div id="counting1"></div>
<img src="../Pictures/BWS + L.A +KUSH/Game.RED_Album_Cover.jpg" alt="red album"><br>
<input type="button" value="VOTE" name="clickOnce" onclick="return countClicks2();" />
<div id="counting2"></div>
</div>
PS我真的会推荐重构代码;它的尺寸是它需要的3倍,这是一个认知障碍。此外,删除不必要的代码(如CSS)和空格以及适当的缩进,可以帮助其他人帮助您。 –