使用JOIN ..how写下这个? 因为这是很慢..IN IN JOIN如何?
SELECT *
FROM table1
WHERE ID IN (SELECT ID
FROM table1
GROUP BY ID
HAVING COUNT(*) = 2
AND MAX(awaiting) = 1)
AND awaiting = 1
所以,我该怎么写?
使用JOIN ..how写下这个? 因为这是很慢..IN IN JOIN如何?
SELECT *
FROM table1
WHERE ID IN (SELECT ID
FROM table1
GROUP BY ID
HAVING COUNT(*) = 2
AND MAX(awaiting) = 1)
AND awaiting = 1
所以,我该怎么写?
SELECT t1.*
FROM table1 AS t1
INNER JOIN
(
SELECT ID
FROM table1
GROUP BY ID
HAVING COUNT(*) = 2
AND MAX(awaiting) = 1
) AS t2 ON t1.ID = t1.ID AND t1.awaiting = t2.awaiting
WHERE t1.awaiting = 1;
这是确切的,我想要的...谢谢...我会接受它作为答案 –
@ MR.Test - 随时欢迎您:) –
这里是join
版本:
SELECT t1.*
FROM table1 t1 join
(SELECT ID
FROM table1
GROUP BY ID
HAVING COUNT(*) = 2 AND MAX(awaiting) = 1
) tsum
on t1.id = tsum.id
WHERE t1.awaiting = 1
我猜awaiting
为0或1。如果是在你的内部查询MAX(awaiting) = 1
是因为多余的WHERE语句awaiting = 1
此外,在这种情况下,您可以使用以下查询。
SELECT *
FROM table1 as T1
WHERE
awaiting = 1
AND
(SELECT count(*) FROM table1 WHERE ID=T1.ID)=2
这是更紧凑和更好,谢谢@ MR.Valex –
您需要一个索引而不是查询重写。 – Ben
但下面的答案完美,非常快... 300%...任何方式...为什么是负面的? –