使用类继承创建模板类型的实例

Question

我遇到了一个我似乎无法解决的问题。

假设我有设置像这样的类：

public abstract class GenericCustomerInformation 
{ 
    //abstract methods declared here 
} 

public class Emails : GenericCustomerInformation 
{ 
    //some new stuff, and also overriding methods from GenericCustomerInformation 
} 

public class PhoneNumber : GenericCustomerInformation 
{ 
    //some new stuff, and also overriding methods from GenericCustomerInformation 
} 

现在假设我有一个功能设置是这样的：

private void CallCustomerSubInformationDialog<T>(int iMode, T iCustomerInformationObject) 
{ 
    //where T is either Emails or PhoneNumber 

    GenericCustomerInformation genericInfoItem; 

    //This is what I want to do: 
    genericInfoItem = new Type(T); 

    //Or, another way to look at it: 
    genericInfoItem = Activator.CreateInstance<T>(); //Again, does not compile 
} 

在CallCustomerSubInformationDialog<T>功能，我有碱基类型的可变GenericCustomerInformation，我想实例化与T（派生类型之一：Emails或PhoneNumber）

一件容易的事情将是使用一堆if的条件，但我不想做任何事情有条件的，因为这将使得比它需要的是我的代码要大得多..

Answer 1

这样的事情也许？ （还是我误解？）

private void CallCustomerSubInformationDialog<T>(int iMode, T iCustomerInformationObject) where T: GenericCustomerInformation, new() 
{ 
    //where T is either Emails or PhoneNumber 
    GenericCustomerInformation genericInfoItem; 
    //This is what you could try to do: 
    genericInfoItem = new T(); 

} 

注意：注意对T的约束......