获取URL参数的值

Question

我想从使用swift的URL获取参数。假设我有以下URL：

http://mysite3994.com?test1=blah&test2=blahblah 

如何获取test1和test2的值？

Answer 1

可以使用belowCode获得帕拉姆

func getQueryStringParameter(url: String, param: String) -> String? { 
    guard let url = URLComponents(string: url) else { return nil } 
    return url.queryItems?.first(where: { $0.name == param })?.value 
} 

呼叫像let test1 = getQueryStringParameter(url, param: "test1")

其他方法，该方法以扩展：

extension URL { 

    public var queryParameters: [String: String]? { 
     guard let components = URLComponents(url: self, resolvingAgainstBaseURL: true), let queryItems = components.queryItems else { 
      return nil 
     } 

     var parameters = [String: String]() 
     for item in queryItems { 
      parameters[item.name] = item.value 
     } 

     return parameters 
    } 
} 

Answer 2

第1步：创建网址分机号码

extension URL { 
    func valueOf(_ queryParamaterName: String) -> String? { 
     guard let url = URLComponents(string: self.absoluteString) else { return nil } 
     return url.queryItems?.first(where: { $0.name == queryParamaterName })?.value 
    } 
} 

步骤2：如何使用扩展

let newURL = URL(string: "http://mysite3994.com?test1=blah&test2=blahblah")! 

newURL.valueOf("test1") // Output i.e "blah" 
newURL.valueOf("test2") // Output i.e "blahblah" 

Answer 3

我也做了一个URL扩展，但把查询参数查找到的下标。

extension URL { 
    subscript(queryParam:String) -> String? { 
     guard let url = URLComponents(string: self.absoluteString) else { return nil } 
     return url.queryItems?.first(where: { $0.name == queryParam })?.value 
    } 
} 

用法：

let url = URL(string: "http://some-website.com/documents/127/?referrer=147&mode=open")! 

let referrer = url["referrer"] // "147" 
let mode  = url["mode"]  // "open"