就刮起一起工作的测试项目,这是我会采取那种方法。它避免了将每个文本框与每个其他文本框进行比较。我评论了这一切为你:)
Private Sub SetBoxColors()
'The keys are textbox texts, the values are the number of times it occurs
Dim UniqueTextsAndUsage As New Dictionary(Of String, Integer)
Dim FirstInstanceTextBoxes As New List(Of TextBox)
'The keys are textbox texts, the values are the colour for the box
Dim UniqueColors As New Dictionary(Of String, System.Drawing.Color)
'Iterate over all the text boxes
' Substitute Me for your Form instance if necessary
For Each TBox As Control In Me.Controls
'Skip things that aren't textboxes
If Not TypeOf TBox Is TextBox Then
Continue For
End If
'If we have seen this textbox text before
If UniqueTextsAndUsage.ContainsKey(TBox.Text) Then
'Increase the usage
UniqueTextsAndUsage(TBox.Text) += 1
If UniqueTextsAndUsage(TBox.Text) = 2 Then
'This is the second usage, generate a colour for this set of boxes
UniqueColors.Add(TBox.Text, GenerateColor(UniqueColors.Count + 1))
End If
'Colour this textbox
' (it won't get the first instance of each unique string)
TBox.BackColor = UniqueColors(TBox.Text)
Else
'We have NOT seen this textbox text before
'Add the first occurence of the text
UniqueTextsAndUsage.Add(TBox.Text, 1)
'Mark this textbox as one we may have to colour later
FirstInstanceTextBoxes.Add(TBox)
End If
Next
'Colour all the first instances
For Each TBox As TextBox In FirstInstanceTextBoxes
'Check there are sufficient uses of this text
If UniqueTextsAndUsage(TBox.Text) > 1 Then
TBox.BackColor = UniqueColors(TBox.Text)
End If
Next
End Sub
Private Function GenerateColor(Id As Integer) As System.Drawing.Color
'Needs more thought - often too dark
Dim KnownColourByIdNumber As System.Drawing.KnownColor = Id
Return System.Drawing.Color.FromKnownColor(KnownColourByIdNumber)
End Function
的GenerateColor功能需要更多的思想,使其产生更好的一些颜色,但我留给你。
您可能还需要将每个框设置为DefaultControl颜色或任何其调用的重置,然后在SetBoxColors顶部运行该框。
'对于x = 1至1000'用'Me.Controls( “文本框” &X)'? –