iPad UIImagePicker问题！

Question

iam试图从照片库导入图像，但当我按导入按钮程序崩溃并收到SGIBART！但我的代码在iPhone上工作正常吗？

这里是我的代码：

.H：

@interface CameraViewController : UIViewController <UIImagePickerControllerDelegate ,UINavigationControllerDelegate> { 

    UIImagePickerController *ipc; 
    UIImageView * image1; 

@property (.......................; 
} 

.M：

- (void)imagePickerController:(UIImagePickerController *)picker didFinishPickingMediaWithInfo:(NSDictionary *)info { 



    image1.image = [[info objectForKey:UIImagePickerControllerOriginalImage]retain]; 
    [[picker parentViewController]dismissModalViewControllerAnimated:YES]; 
    [picker release]; 

} 


- (void)imagePickerControllerDidCancel:(UIImagePickerController *)picker { 

    [[picker parentViewController]dismissModalViewControllerAnimated:YES]; 
    [picker release]; 


} 



     -(IBAction) importImage1 { 

    ipc = [[UIImagePickerController alloc]init]; 
    ipc.delegate = self; 
    ipc.sourceType = UIImagePickerControllerSourceTypePhotoLibrary; 
    [self presentModalViewController:ipc animated:YES]; 
} 

Answer 1

在iPad iOS 3.2上，必须在弹出窗口中显示UIImagePickerController，而不是模态视图。

检查了这一点： http://www.cocos2d-iphone.org/forum/topic/6108

Answer 2

你崩溃，因为你释放选择器，但你没有保留它。您应该删除对[picker release]的呼叫。

您应该切换到使用所有ivars访问器。访问者和dealloc通常是你应该保留或释放你的ivars的唯一地方。选择器不是你的伊娃，你没有创建它，所以你不应该释放它。

你应该花一些时间与Memory Management Programming Guide。您可以在Three Magic Words获得简短版本。