如何从一个句子，通过蟒蛇提取数

Question

下面是一句“建筑是100米高20米宽的”我想提取约高度为100的号码，所以我用

question = input " " 
height = re.findall(r'(\d+) m tall', question) 

但是，有时句子不是“100米高”，而是“100米高”。在这种情况下，我的程序不能再提取我想要的号码了。有没有办法改善我的课程，让它工作，而不管句子包含“高”还是“高”。

Answer 1

您可以通过|检查“高或高”条件：

(\d+) m (tall|high) 

演示：

>>> re.findall(r'(\d+) m (tall|high)', 'a building is 100 m tall and 20 m wide') 
[('100', 'tall')] 
>>> re.findall(r'(\d+) m (tall|high)', 'a building is 100 m high and 20 m wide') 
[('100', 'high')] 

如果你想要不被捕获的话，使用非捕获组：

(\d+) m (?:tall|high) 

Answer 2

>>> import re 
>>> re.findall(r'(\d+) m (?:tall|high)', "a building is 100 m tall and 20 m wide") 
['100'] 
>>> re.findall(r'(\d+) m (?:tall|high)', "a building is 100 m high and 20 m wide") 
['100'] 

Answer 3

根据您的要求，正则表达式应该匹配任何术语“高”或“高”。

  i.e., ?:tall|high 
     where, ?: means 'matches any of' 
       and,  | means 'or' 

因此，解决方案可以像：

>>> re.findall(r'(\d+) m (?:tall|high)', question) 


['100']