当我赞同我的命令行$ PATH,它返回
/usr/local/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin:/Applications/MAMP/Library/bin:/usr/local/git/bin:/usr/X11/bin
当我执行这个PHP代码
exec('echo $PATH; whoami; less /etc/paths; 2>&1')
我得到
string 'echo $PATH; whoami; less /etc/paths; 2>&1' (length=56)
array
0 => string '/usr/bin:/bin:/usr/sbin:/sbin' (length=29)
1 => string 'eric' (length=4)
2 => string '/usr/bin' (length=8)
3 => string '/bin' (length=4)
4 => string '/usr/sbin' (length=9)
5 => string '/sbin' (length=5)
6 => string '/usr/local/bin' (length=14)
7 => string '/Applications/MAMP/Library/bin' (length=30)
8 => string '/usr/bin:/bin:/usr/sbin:/sbin' (length=29)
这是在Mac OS X.谁能告诉我为什么我的最后两个路径元素丢失?
如果我使用getenv(“PATH”),你在apache或cli – mathk 2010-08-07 11:58:38