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我正在为我的网站和这种形式不提交cms。我知道它是一个查询问题,但我无法弄清楚什么是错的。任何帮助?此外,$ db在我的配置中,我确实将它包含在页面的顶部。问题是它没有提交,它只是刷新,没有别的。我也想在后面的表格中显示表格提交内容,但我不知道该怎么做,如果有人能帮助我,这部分也会很棒。Php的mysql的HTML表单提交错误
PHP:
<?php
if(isset($_POST['submit']))
{
$c_name = $_POST['channel_username'];
$v_link = $_POST['video_link'];
$v_title = $_POST['video_title'];
$v_desc = $_POST['vido_description'];
$v_tags = $_POST['video_tags'];
$m_sources = $_POST['music_sources'];
$s_requests = $_POST['special_requests'];
if(empty($c_name) or empty($v_link) or empty($v_title) or empty($v_title) or empty($v_desc) or empty($v_tags))
{
echo 'You must fill in the first 5 fields.';
}
else
{
$getRank = $db->query("SELECT * FROM users WHERE username = '".$_SESSION['username']."'");
while ($row = $getRank->fetch_assoc())
{
$usename = $row['username'];
$rank = $row['rank'];
}
$db->query("INSERT INTO submitted_forms (username, rank, channel_username, video_link, video_title, video_description, video_tags, music_sources, special_requests) VALUES ('$username', '$rank', '$c_name', '$v_link', '$v_title', '$v_desc', '$v_tags', '$m_sources', '$s_requests')");
echo 'Form submitted successfully.';
}
}
?>
HTML:
<form method="POST">
<p>Channel name <input type="text" name="channel_name" required>*</p>
<p>Video Link <input type="text" name="video_link" required>*</p>
<p>Video Title <input type="text" name="video_title" required>*</p>
<p>Video Description <input type="text" name="video_description" required>*</p>
<p>Video Tags <input type="text" name="video_tags" required>*</p>
<p>Music Sources <input type="text" name="music_sources"></p>
<p>Special Requests <input type="text" name="special_requests"></p>
<br></br>
<p><input type="submit" name="submit" value="Submit"></p>
</form>
对不起,HTML和PHP中的字段名称不匹配。因此,这个问题是无用的。 – SteAp
除了不匹配的表单字段/邮件键('c_name'!='channel_username'等),您的查询不匹配单/双引号 - >'“INSERT INTO submitted_forms ... VALUES(''。$ username '',''应该是''INSERT INTO submitted_forms ... VALUES(''。$ username。'','或简单地''INSERT INTO submitted_forms ... VALUES('$ username',' – Sean
也是,你是检查'if(isset($ _ POST ['submit']))',但你的提交按钮没有'submit'这个名字 - >''should''<输入类型=“提交”名称=“提交”值=“提交”>'。它看起来像你需要通过你的HTML和你的PHP,并确保每个表单元素是相同的每个PHP后变量 – Sean