我有简单的类,如this(其行为像Boost :: overload,但具有命名函数(我用它来简化\缩小反射\内省目的))。它对输入参数有多个返回类型有问题(编译器错误3066)。我的代码:重载函数映射容器中的C++函数返回类型:自动扣除失败,编译器错误
#include <iostream>
#include <string>
#include <map>
#include <vector>
template < class T0, class T1 >
class my_map {
typedef T0 type_0;
typedef T1 type_1;
std::map < std::string, type_0 * >T0_var;
std::map < std::string, type_1 * >T1_var;
friend class apitemp;
public:
my_map(int meaningless0 = 42, int meaningless1 = 42) {}
class apitemp {
std::string n_;
my_map *p;
public:
apitemp(std::string name_, my_map * parent):n_(name_), p(parent) {}
operator type_0 *() {
return p->T0_var[n_];
}
operator type_1 *() {
return p->T1_var[n_];
}
};
void insert(std::string name, type_0 * ptr) {
T0_var[name] = ptr;
}
void insert(std::string name, type_1 * ptr) {
T1_var[name] = ptr;
}
apitemp operator[] (std::string n_) {
return apitemp(n_, this);
}
};
template<class out, class in1, class in2>
out hello_world(in1 name, in2 number)
{
name += "!";
std::cout << "Hello, " << name << std::endl;
return number;
}
template<class in1, class in2>
std::string hello_world(in1 name, in2 number)
{
name += "!";
std::cout << "Hello, " << name << std::endl;
return std::string("Yep, we can!");
}
int main() {
int a = hello_world<int, std::string, const int &>("Tim", 25);
std::string b = hello_world<std::string, const int &>("Tim", 25);
my_map<int(std::string, const int &), std::string(std::string, const int &)> myMap;
myMap.insert("my_method_hello", &hello_world<int, std::string, const int &>);
myMap.insert("my_method_hello2", &hello_world<std::string, const int &>);
//int a = myMap["my_method_hello"]("Tim", 25); // error C3066: there are multiple ways that an object of this type can be called with these arguments
//std::string b = myMap["my_method_hello2"]("Tim", 25); // // error C3066: there are multiple ways that an object of this type can be called with these arguments
std::cin.get();
}
如何向其API引入多重返回类型函数? API用户方式有可能无法使用吗?或者至少用一些API用户干扰如
int a = myMap["my_method_hello"]("Tim", 25)::int;
std::string b = myMap["my_method_hello2"]("Tim", 25)::string;
?
“是否有可能用于API用户方式?” - 是谷歌翻译? – sehe 2011-12-15 08:02:31