复杂的查询 - 用分组的列

几张桌子，我有表：复杂的查询 - 用分组的列

Worker (ID, Name) 

Box (ID, Name, ID_Worker) 

BoxColor (ID, Name) 
BoxSize (ID, Name) 

Item(ID, ID_box, ID_BoxColor, ID_BoxSize)

所以我们谁创建项目，并把它们自己的箱子里面的工人。对于我的秘密工作的缘故，我改变了话题，从我的秘密之一EHM箱;）

我想创建raport有列：

Worker.Name | BoxSize.Name | BoxColor(id=0) | BoxColor(id=1) | BoxColor(id=2)

表盒中其它raports使用，因此这桌子的结构可以改变。

我例如想要得到的是：

分组名工人和每个BoxSize，有在列每种颜色计数。例如：

John | X | 2 | 4 | 0 | 
John | XL | 5 | 1 | 0 | 
John | XXL | 2 | 0 | 0 | 
John | S | 3 | 1 | 0 | 
Adam | X | 5 | 4 | 0 | 
Adam | XL | 1 | 3 | 0 | 
Adam | S | 0 | 1 | 0 | 
....

BoxColor是没有那么多颜色的表，以便与不同的子可以硬编码选择像

(select count(*) from BoxColor where ID = 0) 
(select count(*) from BoxColor where ID = 1) 
(select count(*) from BoxColor where ID = 2)

我试图做这样的事情，但查询答循环它永远不会停止 “思考”

select Worker.Name, BoxSize.Name, 
(select count(*) from BoxColor as BoxColor2, Box as Box2, Item as Item2 
    where Box2.ID_Worker = Worker.ID and 
     Item2.ID_Box = Box2.ID and 
     Item2.ID_BoxColor = BoxColor2.ID) and 
     BoxColor.ID = 0) as Red, 
(select count(*) from BoxColor as BoxColor2, Box as Box2, Item as Item2 
    where Box2.ID_Worker = Worker.ID and 
     Item2.ID_Box = Box2.ID and 
     Item2.ID_BoxColor = BoxColor2.ID) and 
     BoxColor.ID = 1) as Green, 
(select count(*) from BoxColor as BoxColor2, Box as Box2, Item as Item2 
    where Box2.ID_Worker = Worker.ID and 
     Item2.ID_Box = Box2.ID and 
     Item2.ID_BoxColor = BoxColor2.ID) and 
     BoxColor.ID = 2) as Blue, 
from Worker, BoxSize, Box, Item 
where 
    Item.ID_Worker = Worker.ID and 
    Item.ID_Box = Box.ID 
    Item.ID_BoxSize = BoxSize.ID 
group by Worker.Name, BoxSize.Name 
having Red > 0, Blue > 0, Green > 0 
order by 1, 2

来源

2013-10-09 gemGreg

考虑处理应用程序级代码/表示层中的数据显示问题（如果有）（例如，一个简单的PHP循环） – Strawberry

我不能在我的网络应用程序中做这个事情，我提出了添加新报告的灵活方法。还有很多其他的，所以我无法为一个报告创建特定的界面:) – gemGreg

也许是这样的：

SELECT 
    Worker.Name, 
    BoxSize.Name, 
    SUM(CASE WHEN BoxColor.id=0 THEN 1 ELSE 0 END) AS BoxColor_0, 
    SUM(CASE WHEN BoxColor.id=1 THEN 1 ELSE 0 END) AS BoxColor_1, 
    SUM(CASE WHEN BoxColor.id=2 THEN 1 ELSE 0 END) AS BoxColor_2  
FROM 
    Worker 
    JOIN Box 
     ON Worker.ID=Box.ID_Worker 
    JOIN Item 
     ON Item.ID_box=Box.ID 
    JOIN BoxColor 
     ON BoxColor.ID=Item.ID_BoxColor 
    JOIN BoxSize 
     ON BoxSize.ID=Item.ID_BoxSize 
GROUP BY 
    Worker.Name, 
    BoxSize.Name

来源

2013-10-09 07:57:25 Arion

复杂的查询 - 用分组的列

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